Question 13 of 41 Using the equations - 2 Fe (s) + 3 Cl₂ (g) → 2 FeCl (s) AH = -800.0 kJ/mol Si(s) + 2 Cl₂ (g) → SiCl (s) AH° = -640.1 kJ/mol Determine the molar enthalpy (in kJ/mol) for the reaction 3 SiCl (s) + 4 Fe (s)→ 4 FeCl (s) + 3 Si (s) 1 4 7 +/-

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter8: Thermochemistry
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Problem 12QAP: The heat of neutralization, Hneut, can be defined as the amount of heat released (or absorbed), q,...
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Question 13 of 41
Using the equations
2 Fe (s) + 3 Cl₂ (g) → 2 FeCl3 (s) AH° = -800.0 kJ/mol
Si(s) + 2 Cl₂ (g) → SiCl (s) AH° = -640.1 kJ/mol
Determine the molar enthalpy (in kJ/mol) for the reaction
3 SiCl (s) + 4 Fe (s)→ 4 FeCl (s) + 3 Si (s)
CHEM103- Lecture Notes -
X
Enthalpy of Formation Rear X
1 2
4
7
+/-
5
8
.
+
kJ/mol
3
6
9
0
E
G
0
P&D
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Update
Submit
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x 100
+
X
7:21 PM
12/6/2022
Transcribed Image Text:M Inbox (2.373)- ftantill@ude X с ← app.101edu.co 56°F Rain off and on 22F-CHEM103-510: General x Aktiv Chemistry G can you divide in hess law- X ‒‒ O Search Question 13 of 41 Using the equations 2 Fe (s) + 3 Cl₂ (g) → 2 FeCl3 (s) AH° = -800.0 kJ/mol Si(s) + 2 Cl₂ (g) → SiCl (s) AH° = -640.1 kJ/mol Determine the molar enthalpy (in kJ/mol) for the reaction 3 SiCl (s) + 4 Fe (s)→ 4 FeCl (s) + 3 Si (s) CHEM103- Lecture Notes - X Enthalpy of Formation Rear X 1 2 4 7 +/- 5 8 . + kJ/mol 3 6 9 0 E G 0 P&D O Update Submit C x 100 + X 7:21 PM 12/6/2022
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