Determine the enthalpy of reaction for HCI(g) + NANO2(s) → HNO2(1) + NaCI(s) 2NACI(s) + H2O(1) → 2HCI(g) + NażO(s) AH° = -507.1 kJ/mol NO(g) + NO2(g) + Na20(s) → 2NANO2(s) AH° = -427.0 kJ/mol NO(g) + NO2(g) → N½0(g) + O2(g) AH° = -43.01 kJ/mol 2HNO2(1) → N2O(g) + O2(g) + H20(1) AH° = +34.02 kJ/mol %3D

World of Chemistry, 3rd edition
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Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
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Chapter10: Energy
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Determine the enthalpy of reaction for HCI(g) + NaNO2(s) → HNO2(1)
+ NaCI(s)
2NaCI(s) + H2O(1) → 2HCI(g) + Na20(s) AH° = -507.1 kJ/mol
NO(g) + NO2(g) + Na2O(s)
NO(g) + NO2(g) → N20(g) + O2(g) AH° = -43.01 kJ/mol
2HNO2(1) →
2NaNO2(s) AH° = -427.0 kJ/mol
→
N20(g) + O2(g) + H2O(I) AH° = +34.02 kJ/mol
Transcribed Image Text:Determine the enthalpy of reaction for HCI(g) + NaNO2(s) → HNO2(1) + NaCI(s) 2NaCI(s) + H2O(1) → 2HCI(g) + Na20(s) AH° = -507.1 kJ/mol NO(g) + NO2(g) + Na2O(s) NO(g) + NO2(g) → N20(g) + O2(g) AH° = -43.01 kJ/mol 2HNO2(1) → 2NaNO2(s) AH° = -427.0 kJ/mol → N20(g) + O2(g) + H2O(I) AH° = +34.02 kJ/mol
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