Question 12 A The fluorination of ammonia is Based on the information, whi AG n << 0 an A molecules do. AG >> 0 ai phase reactants.

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Question 12 D
NH3(g) + 3 F2(g) → NF3(g) + 3 HF(g)
The fluorination of ammonia is represented by the balanced equation above. Approximate values of AG, for the reactants and products are given in the following table.
Compound
AG; (kJ/mol)
NH3 (g)
-16
F2(g)
NF3(g)
-91
HF(g)
-280
Based on the information, which of the following statements best helps to explain whether or not the reaction is thermodynamically favored at 298 K?
AG << 0 and the reaction is thermodynamically favored because the product molecules have more complex structures and greater absolute entropies than the reactant
molecules do.
AGn >> 0 and the reaction is not thermodynamically favored because the total number of moles of gas-phase products is not greater than the total number of moles of gas-
phase reactants.
US
Transcribed Image Text:« < Question 12 D NH3(g) + 3 F2(g) → NF3(g) + 3 HF(g) The fluorination of ammonia is represented by the balanced equation above. Approximate values of AG, for the reactants and products are given in the following table. Compound AG; (kJ/mol) NH3 (g) -16 F2(g) NF3(g) -91 HF(g) -280 Based on the information, which of the following statements best helps to explain whether or not the reaction is thermodynamically favored at 298 K? AG << 0 and the reaction is thermodynamically favored because the product molecules have more complex structures and greater absolute entropies than the reactant molecules do. AGn >> 0 and the reaction is not thermodynamically favored because the total number of moles of gas-phase products is not greater than the total number of moles of gas- phase reactants. US
NH3(9)
16
F2(g)
NF;(g)
-91
HF(g)
-280
Based on the information, which of the following statements best helps to explain whether or not the reaction is thermodynamically favored at 298 K?
AGEn << 0 and the reaction is thermodynamically favored because the product molecules have more complex structures and greater absolute entropies than the reactant
A
molecules do.
B
AG Fan >> 0 and the reaction is not thermodynamically favored because the total number of moles of gas-phase products is not greater than the total number of moles of gas-
phase reactants.
AG" Fzn << 0 and the reaction is thermodynamically favored because the energy released when the bonds in the products are formed is greater than the energy absorbed to
break the bonds in the reactants.
>> 0 and the reaction is not thermodynamically favored because the energy released when the bonds in the products are formed is less than the energy absorbed to
AG
break the bonds in reactants.
US
Transcribed Image Text:NH3(9) 16 F2(g) NF;(g) -91 HF(g) -280 Based on the information, which of the following statements best helps to explain whether or not the reaction is thermodynamically favored at 298 K? AGEn << 0 and the reaction is thermodynamically favored because the product molecules have more complex structures and greater absolute entropies than the reactant A molecules do. B AG Fan >> 0 and the reaction is not thermodynamically favored because the total number of moles of gas-phase products is not greater than the total number of moles of gas- phase reactants. AG" Fzn << 0 and the reaction is thermodynamically favored because the energy released when the bonds in the products are formed is greater than the energy absorbed to break the bonds in the reactants. >> 0 and the reaction is not thermodynamically favored because the energy released when the bonds in the products are formed is less than the energy absorbed to AG break the bonds in reactants. US
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