Question 11 ptsThe drive shaft of a car is subjected to both bending and torsion. The torque, T, is constant at400 Nm and the bending moment has the following cycle parameters: mean moment of Mm= 250 Nm and alternating moment of Ma = 800 Nm.The shaft is forged from high-carbon steel with an ultimate strength Sut = 615 MPa andendurance limit Se' = 307.5 MPa. The reliability must be 90% and the safety factor is nf = 2.7.For the analysis of the stress concentration, assume the proportions shown in the figure and asize factor kb = 0.9. To evaluate the factors kt, kts, q and qs, it is recommended to use Excelspreadsheets. Calculate the first estimate of the minimum shaft diameter (d) in millimetersusing the Goodman criterion.1≥4DIdD/d = 1.33r/d = 0.25r≥ 4 mm (To evaluate q and qs, it is initially recommended r = 4 mm)

To calculate the minimum shaft diameter d using the Goodman criterion, we need to follow these…

Answered: Question 1 1 pts The drive shaft of a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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1) A shaft is loaded in bending and torsion such that Ma = 70 N-m, Ta = 45 N-m, Mm = 55 N-m, and Tm = 35 N-m. For the shaft, Sut = 700 MPa and Sy = 560 MPa. A fully corrected Se = 210 MPa is assumed. Let K; = 2.2 and Kfs = 1.8. With a design safety factor of 2.0, determine the minimum acceptable diameter of the shaft using: a. DE-Modified Goodman criterion b. DE-ASME Elliptic criterion C. DE-Gerber criterion
1.
Compute the contact stress number for the gear fain pair driven directly by an electrical motor. The driven machthe is concrete mixture with moderate shock, the other data are given below. Ks= 1.00, Km 1.21, Vt =1527 St/min, Av-11 Pd= 6, np= 1750rp.m, Np 20, No= 70, F=2.00/n Tp = 900ib, Dp= 3:333 in The material used for pioin an gear is Steel
Using the DE-Goodman criteria and a design factor of 1.5, calculatethe diameter based on the shaft’s loadings and your guess for theshaft’s diameter at the critical location. What is the shaft diameter? Material: 1030 Q and T → Sᵤₜ: 848 MPa, Sy: 648 MPa TM=306 NM MA=698.28 NM ta=0 mm=0
3. A motor is connected by a belt to pulley B. T, is the tight-side tensile force equal to 1800 N. The shaft spins at a constant speed, 650 rpm. The power delivered by the motor is 12.6 kW. On pulley A, connected to the load, the slack side of the belt has a tension equal to th of the tight side. b T T, B d shaft Dimensions are as follows: da 200 тm 300 тт | 250 тm |180 тm | 250 тm 26 тm dB dahaft a We analyzed a problem similar to this on Test 01 using static failure theories. Is this strictly correct? Because the shaft is spinning, would not a material particle see a time-varying reversal of the the bending stress as in the R.R. rotating beam test? Would a particle see a reversal of the torsional shear stress? Assume Sut = 370 MPa and Sy = 300 MPa. Ignore Marin factors. Ignore stress concentrations. Ignore direct shear stress (that due to V). Find the safety factors with respect to fatigue and yielding. Be guided by section 6-14 on combined loading.
A protective ﬂange coupling is used to connect two shafts and transmit 7.5 kW power at 720 rpm. The design torque is 150% of the rated torque. The shafts and bolts are made of plain carbon steel 30C8 (Syt = 400 N/mm2) and the factor of safety is 5. Assume, Syc = 1.5 Syt and Ssy = 0.5 SytThe ﬂanges are made of cast iron.Calculate:(i) diameter of the shafts;(ii) number of bolts; and(iii) diameter of the bolts.
Required information A helical coil compression spring is needed for food service machinery. The load varies from a minimum of Fmin 4 lbf to a maximum of Fmax 16 lbf. The spring rate k is to be 9.5 Ibf/in. The outside diameter of the spring cannot exceed 2.5 in. The spring maker has available suitable dies for drawing 0.08-in-diameter wire. Use a fatigue design factor nf of 1.5 and the Gerber-Zimmerli fatigue-failure criterion. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Determine the values for each of the following for a value of 0.08 in: The torsional modulus of rupture, Ssu, is kpsi. Torsional yield strength, Ssy, is | kpsi. The endurance strength, assuming unpeened spring wire, Sse, is The value of the mean diameter, D, is in. The alternating shear stress, Ta, is The fatigue factor of safety, nf, is The free length, Lo, is The critical length, LO(cr), is in. in. kpsi. kpsi.
Question Three An intermediate shaft is running at constant speed as shown in Figure 3. The shaft to be made from AISI1040 cold rolled. The shaft is subjected to torque which is fluctuates from Tas to 0.5 Trux torque in phase with a steady bending. The reliability is 90% and stress concentration factor Ki = 1.5 for bending and Ks = 2 for torsion for 3 mm fillet radius. a. Use modified Goodman theory to determine the minimum shaft diameter required to obtain the fatigue factor of safety of 2.5 b. Calculate Langer first -cycle-yielding factor of safety F. = 6 kN R75 mm R50 mm 150 mm 350 mm F= 9 kN 250 mm Figure 3
Ex. Determine the safety factor for the bracket rod shown below for N = 6 x 107 Cycles. The notch radius at the wall is Y=0.25 cm.. the braket is made from Aluminum 2024, Cold-drawn with σy, 290 MP 441 MPa. L = 10 cm, a = 8 cm, d = 2cm. "Out = d Wall A rod arm a F
4) Compute the fatigue life of a rotating hub and shaft assembly, if at a critical point in the shaft, the state of stress is described by σxx,max = 1000 MPa, σxx,min=-800 MPa, Txy,max = 300 MPa, Txy,min = -100 MPa, and σyy = σzz = Txz = σyz = 0. Employ the maximum shear stress thory of failure together with modified Goodman criterion. Take σ₁ = 2400 MPa and the fatigue-strength reduction factor K=1. [Use fracture stress as 0.9 times the ultimate stress, endurance stress as (1/3) times K times the ultimate stress, N = 103 cycles and Ne=108 cycles]
A rigid block is supported by two cables having the same diameter of 4 mm. Cable S1 is made of AISI 1050 cold drawn steel with E=200,000 MPa, Sy=580 MPa, and Sult=690 MPa; cable S2 is made of AISI 1020 cold drawn steel with E=200,000 MPa, Sy=390 MPa, and Sult=470 MPa. Determine the maximum number of cycles n3 due to the following history of P.
A 76.2 mm diameter shafting of SAE 1040 grade, cold, rolled, having yield point of 50 ksi and with a ¾ x ¾ x 5 inches key. Compute the minimum yield point in the key in order to transmitt he torque of the shaft. The factor of safety to use is 2 and Sys = 0.5 Sy. (Ans: 47.12 ksi)

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