Q9. A Random Variable X has an unknown distribution, a known mean of 10and an unknown variance, oʻ. To test a claim that the distribution is nolonger 10, a random sample of 100 of X was collected which gave asample mean, x of 9.8 and a sample variance, s? = 16.Working at the 5% Significance level what is the reject region?A. z<-1.96 AND z> 1.962%3DB. z>-1.96 AND z< 1.96C. z< -2.57 AND z> 2.57D. z<-1.96 OR z> 1.96О А. АО В. ВО С. СO D. D

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Answered: Q9. A Random Variable X has an unknown…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The owner of a tire company wants to determine how long a new type of tire tread will last by measuring the length of time, in days, it takes for the tire tread to reach 2 mm. Let u = the true mean number of days it takes for the tire tread to wear to 2 mm. Which of the following sample sizes will have the least variability in the sampling distribution of the sample mean? 25 O35 O45 55
The data in the following Table 3 represent the number of hours of relief provided by five different brands of headache tablets administered to 15 subjects experiencing fevers of 38°C or more. Perform the analysis of variance and test the hypothesis at the 0.05 level of significance that the mean number of hours of relief provided by the tablets is the same for all five brands. Discuss the results. Table 3: Hours of relief by different brands of headache tablets Tablet Relief duration (in hour) Brand A B C D E 5.2 9.1 3.2 2.4 7.1 4.7 7.1 5.8 3.4 6.6 8.1 8.2 2.2 4.1 9.3
Q10. A Random Variable X has an unknown distribution, a known mean of 10 and an unknown variance, oʻ. To test a claim that the distribution is no longer 10, a random sample of 100 of X was collected which gave a sample mean, x of 9.8 and a sample variance, s? = 16. What is the hypothesis testing decision based on this data? A. Reject the Null: x = 10. C. Don’t Reject the Null: µ = 10. B. Don't reject the Null: x = 10 %3D D. Reject the Null: µ = 10. O A. A В. В ОС. С O D. D
B5. Two independent samples from normally distributed populations have values {2, 5, 4, 1} for sample 1, and {2,3, 2, 2, 4} for sample 2. Test at the 1% level H9: of = o, H;: of > o3. As part of your answer, state an appropriate test statistic and its distribution under Ho. Hint: You may need to use one of these percentiles, F3,4(1%) = 16.694, F43(1%) = 28.710, F3,4(0.5%) = 24.259, F13(0.5%) = 46.195. %3D !! %3D
Mean 1001 206 Levene's Test for Equality of Variances Sig. 15.578 <.001 .510 1.402 df Sig. (2-tailed) 1205 .014 261.832 035 -3.168 -3.168 Std. Error Difference 3. Do Whites spend a significantly different amount of time on the internet (WWWHR) than Blacks? Group Statistics Std. Error Race of respondent N Std. Deviation Mean Www.hours per week WHITE 13.29) (16.124) BLACK 16.46 20.120 Independent Samples Test t-test for Equality of Means Mean t Difference Www hours per week -2.455 Equal variances assumed -2.124 Equal variances not assumed 1.291 1.492 95% Confidence Interval of the Difference Lower Upper -5.701 -6.106 -.636 -.231
A researcher wants to select a sample from a population with a mean (µ)= 60 and administer a treatment to individuals in the sample. He thinks the treatment will help improve scores. a. State the hypotheses for a one-tailed test. b. For a one-tailed test, would the critical region be located in the positive or right-hand tail of the distribution, or in the negative or left-hand tail of the distribution?
A yogurt producer claims the variance on their yogurt containers is 4 grams or less . A sample of 30 containers had a sample variance of 9 grams. We want to test if the variance is greater than 4 (a=0.05) The correct alternative hypothesis to test the producer claim is : Select one: O a. HA :02 s4 O b. HA :02 > 16 29 O C. HA :02 > 4 36 O d. Ho :02 > 2 Finis e Next page
12.A sample of n = 16 scores has a mean of M = 65 and an estimated standard error of 2 points. What is the sample variance? s2 = 64 c. s2 = 16 а. b. s2 = 36 d.s? = 4
Write complete and legibly.
(ONE WAY ANOVA) Find the ff: a. mean & variance of each sample b. find the grand mean c. find the between & within
A researcher takes sample temperatures in Fahrenheit of 16 days from Miami and 14 days from Atlanta. Use the sample data shown in the table. Test the claim that the mean temperature in Miami greater than the mean temperature in Atlanta. Use a significance level of α=0.10α=0.10.Assume the populations are approximately normally distributed with unequal variances.Note that list 1 is longer than list 2, so these are 2 independent samples, not matched pairs. Miami Atlanta 68.3 73.6 83.1 69.3 79.1 54.9 72 81.1 72.8 78.6 83.3 54 82.7 36.1 80.7 44.3 87 58.4 83.1 50.8 77.4 60.5 86.1 61.2 76.3 46.8 74.5 54.4 83.3 78.5 The Null Hypotheses is: H0: μ1 - μ2 = 0 What is the alterative hypothesis? Select the correct symbols for each space. (Note this may view better in full screen mode.)HA: μ1 - μ2 Based on these hypotheses, find the following. Round answers to 4 decimal places. Test Statistic = p-value = The p-value is The correct…
Incorrect. The weight of boxes of candy is a normal random variable with mean and variance 1/10 pound2. The prior distribution for u is normal with mean 5.01 pound, and variance 1/25 pound2. A random sample of 9 boxes gives a sample mean of x = 5.02 pound. Find the Bayes estimate of u. Round your answer to three decimal places. ji i 5.015

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