Suppose we are given a sample of 60 observations from a distribution whose mean is 0 and variance is 3/5 Find approximately the probability that the sample mean lies in the interval (-0.05,0.05). Options: 0.000625 0.383 0.6915 1
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Suppose we are given a sample of 60 observations from a distribution whose
Find approximately the probability that the sample mean lies in the interval (-0.05,0.05).
Options:
- 0.000625
- 0.383
- 0.6915
- 1
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- Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P9, the 9th percentile. This is the bone density score separating the bottom 9% from the top 91%. Which graph represents P9? Choose the correct graph below.A population has a mean of and standard deviation of 12. A sample of 36 observations will be taken . The probability tha the sample mean will be between 80.54 and 88.9 is A 0.7200 O B 0.0347 C 0.9511 D 8.3600Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees and standard deviation of 1.00degreesC. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to Upper P 90, the 90th percentile. This is the temperature reading separating the bottom 90% from the top 10%.
- Assume the data set described is normally distributed with the given mean and standard deviation, and with n total values. Find the approximate number of data values that will fall in the given range. Mean-8 Standard deviation-1.5 n-45 Range: 6.5 to 9.5 In this case, we expect about 52 data values to fall between 6.5 and 9.5.Thirty percent of people did not visit their doctor's, offices last year. Let x be the number of adults in a random sample of 12 adults who did not visit their doctors’ offices last year. The standard deviation of the probability distribution of x is approximately Could you show the steps and equations used, please?Suppose in 2000, the science scores for female students had a mean of 146 with a standard deviation of 35. Assume that these scores are normally distributed with the given mean and standard deviation. _________________ of the female students scored between 76 and 216
- A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1522 and the standard deviation was 311. The test scores of four students selected at random are 1950, 1260, 2190, and 1410. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The z-score for 1950 is. (Round to two decimal places as needed.)Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P70, the 70-percentile. This is the temperature reading separating the bottom 70% from the top 30%.P70 = °CA standardized exam's scores are normally distributed. In a recent year, the mean test score was 1458 and the standard deviation was 312. The test scores of four students selected at random are 1860, 1220, 2150, and 1340. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The z-score for 1860 is (Round to two decimal plaes as needed.)
- The Intelligence Quotient (IQ) test scores for adults are normally distributed with a population mean of 100 and a population standard deviation of 20. What is the probability we could select a sample of 20 adults and find the mean of this sample is less than 95? 0.1314 0.7372 0.3686 0.7098The mean time it takes a group of students to complete a statistics final exam is 98 minutes, and the standard deviation is 9 minutes. Within what limits would you expect approximately 95% of the students to complete the exam? Assume the variable is approximately normally distributed.If we meet these conditions, the sampling distribution of the mean will have a normal shape and ... The mean of the sampling distribution will be u, (i.e., the same as the population mean) and the standard deviation of the sampling distribution will be (that's the population standard deviation divided by the square root of the sample size). In the AP Stats Guy video, he talks about the number of text messages his students send during class. Suppose the average number of text messages his students send during class is u = 30 text messages. If we take samples of say, n = 36 students at a time, we would expect the mean of the sampling distribution we create to be the same as the population mean, 30 text messages. If we can further say that standard deviation of the number of text messages is 12 text messages, by how much would we expect the sample means to vary? (hint, use the formula above) text messages