Q8: From the P-V diagrams below find the network for the cycle process of 1 molegas at 27°C.AP (105Pa)200 kPaPB100 kPa0.05m³Isotherm0.1m³V9.006.003.0021V (m³)2.00 4.006.00

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Answered: Q8: From the P-V diagrams below find…

College Physics

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Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note Note that 1 literxatmosphere is equal to 101.325 joule. Sol": given Heat of melting ice at 1 atm pressure = 1.4363 kca kcal/ 2 = 1.4363 kcal/mole mole volume of ice = 0·0196 lts " water = 0.018 lts @ work done is define as w=pdv » w = P(V₁ hot W = 1 (0·018-00196) W = 0·0016 Cal Pay Kat Ans
The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If I mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule.
See photo attached. What is the change in internal energy of the gas from A to B?
The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule. Please solve with clarification of laws and with the order of units [Cal]
The volume of a gas exiting a delivery device is 0.2 liters at a temperature of 150C. The gas then heats up to 500C before it is delivered to a patient. Assume the pressure is constant. Determine the volume of gas when the patient receives it. Use the temperature in K.
Suppose V₁=160 cm³ in (Figure 1). Figure p (atm) 3- T 2. 1 V₁2V, 1 of 1 V (cm') 3V₁ Part A How much work is done per cycle by a gas following the pV trajectory of the figure? Express your answer to two significant figures and include the appropriate units. ▸ View Available Hint(s) Wot Submit Value < Return to Assignment Units Provide Feedback ?
A sample of an ideal gas goes through a full cycle, returning to the same pressureand volume. It does this by undergoing a. an isobaric expansion,b. a constant-volume reduction in temperature,c. and then an isothermal process back to its initial state. Draw the pV-diagram for this full cycle.
Determine the work done in S.l. unit for each process.
-70 J of work are done on the gas in the process shown in (Figure 1). Figure p (kPa) P₁ 0+ 0 100 200 300 < 1 of 1 V (cm³) Part A What is p₁ in kPa? Express your answer in kilopascals. P1 = Submit VE ΑΣΦ Provide Feedback Request Answer ***** ? kPa
The pV diagram in (Figure 1) shows a process abc involving 0.550 mol of an ideal gas. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of A cyclic process. Figure 8.0 6.0 4.0 2.0 p(Pax 105) 0.020 0.040 0.060 b 0.080 1 of 1 -V(m³) What was the temperature of this gas at points a, b, and c? Enter your answers separated by commas. LIVE ΑΣΦ Tas To Tc 937.7,7654.12, 12296.59 Submit X Incorrect; Try Again; 3 attempts remaining Part B Previous Answers Request Answer How much work was done by or on the gas in this process? Express your answer in joules. W = 2.1×104 J Submit Previous Answers Part C Correct The work done in a process is the area under the curve in the pV diagram. The work done by the gas is positive since the volume increases. The magnitude of the work is the area under the curve: W = (2.0 × 105 Pa + 5.0 × 105 Pa)(0.070 m³ – 0.010 m³) = 2.10 × 10¹ J VO How much heat had to be put in during the process to increase the internal energy of…
Answer the following questions about the PV diagram shown in the picture. Question 1: How much work is done by the gas in each cycle ADCA? Answer in joules. Question 2: How much work is done by the gas in each cycle ADBA? Answer in joules. Question 3: How much work is performed in the process AD? Answer in joules.

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Q8: From the P-V diagrams below find the network for the cycle process of 1 mole gas at 27°C. A P (105Pa) 200 kPa P B 100 kPa 0.05m³ Isotherm 0.1m³ V 9.00 6.00 3.00 2 1 V (m³) 2.00 4.00 6.00