For a sphere of radius R = 12.1 m that is charged with a non-uniform volume charge density:bp(r) = as=ar +with a =figure).6.8 x 10-12 C/m² and b = 6.6 × 10-12 C/m² and r is the distance from the center of the sphere (seeRCalculate the electric potential at distance r = 8.5 m from the center.Assume that the potential on the surface of the sphere equals to zero, that is (R) = 0.21.0 x

Step 1: Step 2: Step 3: Step 4:

Answered: For a sphere of radius R = 12.1 m that…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Consider a very large, flat plate with surface charge density 2.06 nC/m2. Give the electric potential (in V) a distance 6.28 m from the plate. Take the plate itself to have zero electric potential.
If the electric potential is given by V(x, y) = (12 V/m2) x2 + (3 V/m) y determine the magnitude of the electric field, in V/m, at the origin.
A charge q1=7x10-6 is located at the origin, and a second charge q2=-5x10-6 is locatedon the x-axis, 0.30 m from the origin. Find the electric potential at (0.15, 1) m
It is known that the electric quantity Q is uniformly distributed on the spherical surface of radius R, that is, the electric charge per unit area isQ/4piR^2Find the electric potential distribution generated by this charged sphere in space.
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The electric potential on the surface of a charged conducting sphere is 210 V, and 10.0 cm farther from the center of the sphere the potential is 140 V. (a) Determine the radius of the sphere. HINT: Use a ratio of the two given potentials to solve for the radius. 20 cm (b) Determine the charge on the sphere. 4.67 nC The electric potential on the surface of another charged conducting sphere is 240 V, and 10.0 cm farther from the center the magnitude of the electric field is 410 V/m. (c) Determine all possible values for the radius of the sphere. (Enter your answers from smallest to largest. If only one value exists, enter "NONE" in the second answer blank.) HINT: Use the ratio of the potential at the surface to the E field at the surface plus 10.0 cm to solve for the radii. cm r2 = cm (d) Determine the charge on the sphere for each value of r. (If only one value exists, enter "NONE" in the second answer blank.) 91 = nC 92 =
The electric field of ?(?) = 1/r + 3(v/m), where r is the distance from the origin, is applied in a region of space. Find the electric potential between the two points ?1=0,5 m and r2 =2 m . Hint: you will have to use integration here, with r1 and r2 as your bounds of integration
In three corners of a square with d=4 cm side length, there are point charges (in red) Q1=-28 pC, Q2 =-117 pC and Q3 =-57 pC. Calculate the difference between the potentials in the middle (V2) and in the fourth corner (V1) . (V2-V1) Write your answer in V with 2 decimals.
An infinitely long metal cylinder has radius R0 and charge per unit length λ. It is held at potential V0, which you should use as the reference point for this problem. The cylinder is solid (not hollow) and in electrostatic equilibrium. (a) Find the electric potential outside the cylinder, for a distance r > R0 from the center of the cylinder. (b) Find the electric potential inside the cylinder, at a distance r < R0 from the center of the cylinder.
The electric potential of a system is presented by the figure shown below. Find the x-component of the electric field at points A, B, and C if Vo = 10 V and x₁ = 20 cm, x2 = 80 cm, x3 = 120 cm. V Vo A X₁ B = The x-component of E-field at point A, EA The x-component of E-field at point B, EB = The x-component of E-field at point C, Ec = 19.714 X₂ C X3 X Units Select an answer ✓ Units Select an answer ✓ Units Select an answer X
If you already know the electric field, you can find the change in electrostatic potential between two points A and B by integrating the field along an arbitrary path joining these two points, VB - VA = while the field at r > R is == E(r) = 1 Recall from Gauss's law that the magnitude of the electric field E(r) at a radial distance r ≤R from the center of a uniformly charged sphere with total charge Q and radius R is given by E(r) = B Ē. ds. 1 Q 4π€0 R3¹ 1 Q p2 4πεο If the charge Q is positive, the field points radially out. We will now analyze the electric potential due to a uniform spherical charge distribution.
The charge density on a disk of radius R = 11.6 cm is given by o = ar, with a = 1.46 μC/m³ and r measured radially outward from the origin (see figure below). What is the electric potential at point A, a distance of 44.0 cm above the disk? Hint: You will need to integrate the nonuniform charge density to find the electric potential. You will find a table of integrals helpful for performing the integration. V R A

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