8. Figure below shows a ring of outer radius R = 13.0 cm and inner radius rinner = 0.200R. It has uniform surface charge density 6 = 6.20 pC/m² . With V = 0 at infinity, find the electric potential at point P on the central axis of the ring, at distance z = 2.00R from the center of the ring.
8. Figure below shows a ring of outer radius R = 13.0 cm and inner radius rinner = 0.200R. It has uniform surface charge density 6 = 6.20 pC/m² . With V = 0 at infinity, find the electric potential at point P on the central axis of the ring, at distance z = 2.00R from the center of the ring.
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Transcribed Image Text:8. Figure below shows a ring of outer radius R = 13.0 cm and inner
radius l'inner = 0.200R. It has uniform surface charge density
0 = 6.20 pC/m². With V = 0 at infinity, find the electric potential at point P
on the central axis of the ring, at distance z = 2.00R from the center of the
ring.
6
dQ
K √ ₁7 - Pl
What is your dQ? What is your infinitesimal area element?
(a) Start with the formula for the potential: V = k
What are your vectors r and r'? What is the distance to point P?
What is dV? Potential due to a small ring of charge on the disk?
(b) Write out the integral that you need to compute to get V. What are the
bounds?
(c) Once you get an expression for V, solve numerically.
(d) Check to see if the units of your expression makes sense for V.
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