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A beam of electrons are created by an electron gun and they move horizontally with a speed of 3.3 x10^7 m/s. The electrons enter a 2.0cm long gap between the two parallel plates where the electric field intensity is 5.0 x 10^4 N/C down. See diagram Determine a-the time to cross the plates B-the magnitude and direction of the acceleration in the region between the plates C-the final velocity of the electron as it leaves the plates(both magnitude and direction) Deflection plates L-2.0 cm È =(5.0 x 10' N/C, down)

A beam of electrons are created by an electron gun and they move horizontally with a speed of 3.3 x10^7 m/s. The electrons enter a 2.0cm long gap between the two parallel plates where the electric field intensity is 5.0 x 10^4 N/C down. See diagram Determine a-the time to cross the plates B-the magnitude and direction of the acceleration in the region between the plates C-the final velocity of the electron as it leaves the plates(both magnitude and direction) Deflection plates L-2.0 cm È =(5.0 x 10' N/C, down)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A beam of electrons are created by an electron gun and they move horizontally with a speed of 3.3 x10^7 m/s. The electrons enter a 2.0cm long gap between the two parallel plates where the electric field intensity is 5.0 x 10^4 N/C down. See diagram Determine a-the time to cross the plates B-the magnitude and direction of the acceleration in the region between the plates C-the final velocity of the electron as it leaves the plates(both magnitude and direction) Deflection plates L-2.0 cm È =(5.0 x 10' N/C, down)
Transcribed Image Text:A beam of electrons are created by an electron gun and they move horizontally with a speed of 3.3 x10^7 m/s. The electrons enter a 2.0cm long gap between the two parallel plates where the electric field intensity is 5.0 x 10^4 N/C down. See diagram Determine a-the time to cross the plates B-the magnitude and direction of the acceleration in the region between the plates C-the final velocity of the electron as it leaves the plates(both magnitude and direction) Deflection plates L-2.0 cm È =(5.0 x 10' N/C, down)
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