Q#6: The following balanced equation will be useful to answer the two questions that follow. MM's are given below each molecule or salt. 2 KMNO4 + 5 K2C204 + 16 HCI → 2 MnCl2 + 12 KCI + 10 CO2 + 8 H20 158.04 166.22 36.46 125.84 74.55 44.01 18.0 part A) How many grams of potassium chloride will be produced from the reaction of 25.00 mL of a 0.123 M solution of potassium permanganate? part B) The only gas in the above equation is CO2 (MM = 44.01 g/mol). If 45.3 g of potassium permanganate are completely reacted in a 4.0 L container at 345 K, what is the resulting pressure?

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Q#6:
The following balanced equation will be useful to answer the two questions that
follow. MM's are given below each molecule or salt.
2 KMNO4 + 5 K2C204 + 16 HCI 2 MnCl2 + 12 KCI + 10 CO2 + 8 H20
158.04
166.22
36.46 125.84
74.55 44.01 18.0
part A)
How many grams of potassium chloride will be produced from the reaction of
25.00 mL of a 0.123 M solution of potassium permanganate?
part B)
The only gas in the above equation is CO2 (MM = 44.01 g/mol). If 45.3 g of
%3D
potassium permanganate are completely reacted in a 4.0 L container at 345 K, what is
the resulting pressure?
Transcribed Image Text:Q#6: The following balanced equation will be useful to answer the two questions that follow. MM's are given below each molecule or salt. 2 KMNO4 + 5 K2C204 + 16 HCI 2 MnCl2 + 12 KCI + 10 CO2 + 8 H20 158.04 166.22 36.46 125.84 74.55 44.01 18.0 part A) How many grams of potassium chloride will be produced from the reaction of 25.00 mL of a 0.123 M solution of potassium permanganate? part B) The only gas in the above equation is CO2 (MM = 44.01 g/mol). If 45.3 g of %3D potassium permanganate are completely reacted in a 4.0 L container at 345 K, what is the resulting pressure?
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