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For the reaction below, balance the chemical equation and then calculate how many grams of NH3 form when each amount of reactant completely reacts.                                             N2H4 (l) → NH3 (g) + N2 (g)  a. 5.3 mol N2H4 b. 32.5 g N2H4 c. 14.7 kg N2H4

For the reaction below, balance the chemical equation and then calculate how many grams of NH3 form when each amount of reactant completely reacts.                                             N2H4 (l) → NH3 (g) + N2 (g)  a. 5.3 mol N2H4 b. 32.5 g N2H4 c. 14.7 kg N2H4

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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For the reaction below, balance the chemical equation and then calculate how many grams of NH3 form when each amount of reactant completely reacts.

                                            N2H4 (l) → NH3 (g) + N2 (g) 

a. 5.3 mol N2H4

b. 32.5 g N2H4

c. 14.7 kg N2H4

 

Expert Solution
Step 1

Given 

Unbalance reaction 

     N2H4(l)   →  NH3(g)  +  N2(g)

(a)  Number of mole of N2H4  = 5.3 mole 

       Mass of NH3  = ? 

(b) Mass of N2H4  =  32.5 gram 

     Mass of NH3    =  ? 

(c)  Mass of N2H4  = 14.7 kg

                              = 14700 gram         ( 1 Kg = 1000 gram ) 

      Mass of NH3    = ?

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