Use the chemical equation to answer the question. 2Ag(s) + H2S(g) → Ag2S(s) + H2(g) The molar mass of silver (Ag) is 108 g/mol. The molar mass of sulfur (S) is 32 g/mol. The reaction uses 0.04 mol of silver. Which steps show how to determine the mass of silver sulfide (Ag2S) produced in the reaction? 2(108 g/mol)+32 g/mol=248 g/mol; (248 g/mol)(0.04 mol)=9.92 108 g/mol+2(32 g/mol)=172 g/mol; (172 g/mol)(0.02 mol)=3.44 g
Use the chemical equation to answer the question. 2Ag(s) + H2S(g) → Ag2S(s) + H2(g) The molar mass of silver (Ag) is 108 g/mol. The molar mass of sulfur (S) is 32 g/mol. The reaction uses 0.04 mol of silver. Which steps show how to determine the mass of silver sulfide (Ag2S) produced in the reaction? 2(108 g/mol)+32 g/mol=248 g/mol; (248 g/mol)(0.04 mol)=9.92 108 g/mol+2(32 g/mol)=172 g/mol; (172 g/mol)(0.02 mol)=3.44 g
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Use the chemical equation to answer the question.
2Ag(s) + H2S(g) → Ag2S(s) + H2(g)
The molar mass of silver (Ag) is 108 g/mol. The molar mass of sulfur (S) is 32 g/mol. The reaction uses 0.04 mol of silver. Which steps show how to determine the mass of silver sulfide (Ag2S) produced in the reaction?
- 2(108 g/mol)+32 g/mol=248 g/mol; (248 g/mol)(0.04 mol)=9.92
- 108 g/mol+2(32 g/mol)=172 g/mol; (172 g/mol)(0.02 mol)=3.44 g
- 108 g/mol+2(32 g/mol)=172 g/mol; (172 g/mol)(0.04 mol)=6.88 g
- 2(108 g/mol)+32 g/mol=248 g/mol; (248 g/mol)(0.02 mol)=4.96 g
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