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Q5) Kinetic Energy of Rotation and Rolling Motion Am = 2kg ring has a radius of r = 0.5m. The moment of inertia of a ring is I = m r². The ring has an initial speed of v = 1 m/s on the horizontal surface. It rolls, without slipping, along the surface and up the ramp, where it stops when it reaches a height h. v=1m/s a) What is the angular velocity of the ring when it is on the horizontal surface? v=0 b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring? c) Use Conservation of Energy to find the maximum height of the ring, h. Show all your work. Solve the problem using variables. Only substitute numbers in the very last step.

Q5) Kinetic Energy of Rotation and Rolling Motion Am = 2kg ring has a radius of r = 0.5m. The moment of inertia of a ring is I = m r². The ring has an initial speed of v = 1 m/s on the horizontal surface. It rolls, without slipping, along the surface and up the ramp, where it stops when it reaches a height h. v=1m/s a) What is the angular velocity of the ring when it is on the horizontal surface? v=0 b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring? c) Use Conservation of Energy to find the maximum height of the ring, h. Show all your work. Solve the problem using variables. Only substitute numbers in the very last step.

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Q5) Kinetic Energy of Rotation and Rolling Motion Am = 2kg ring has a radius of r = 0.5m. The moment of inertia of a ring is I = m r². The ring has an initial speed of v = 1 m/s on the horizontal surface. It rolls, without slipping, along the surface and up the ramp, where it stops when it reaches a height h. v=1m/s a) What is the angular velocity of the ring when it is on the horizontal surface? v=0 b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring? c) Use Conservation of Energy to find the maximum height of the ring, h. Show all your work. Solve the problem using variables. Only substitute numbers in the very last step. h
Transcribed Image Text:Q5) Kinetic Energy of Rotation and Rolling Motion Am = 2kg ring has a radius of r = 0.5m. The moment of inertia of a ring is I = m r². The ring has an initial speed of v = 1 m/s on the horizontal surface. It rolls, without slipping, along the surface and up the ramp, where it stops when it reaches a height h. v=1m/s a) What is the angular velocity of the ring when it is on the horizontal surface? v=0 b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring? c) Use Conservation of Energy to find the maximum height of the ring, h. Show all your work. Solve the problem using variables. Only substitute numbers in the very last step. h
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