A m = 2kg ring has a radius of r = 0.5m. The moment of inertia of a ring is I = m r2. The ring has an initial speed of v = 1 m/s on the horizontal surface. It rolls, without slipping, along the surface and up the ramp, where it stops when it reaches a height h. a) What is the angular velocity of the ring when it is on the horizontal surface? b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring? c) Use Conservation of Energy to find the maximum height of the ring, h. Solve the problem using variables.
Angular Momentum
The momentum of an object is given by multiplying its mass and velocity. Momentum is a property of any object that moves with mass. The only difference between angular momentum and linear momentum is that angular momentum deals with moving or spinning objects. A moving particle's linear momentum can be thought of as a measure of its linear motion. The force is proportional to the rate of change of linear momentum. Angular momentum is always directly proportional to mass. In rotational motion, the concept of angular momentum is often used. Since it is a conserved quantity—the total angular momentum of a closed system remains constant—it is a significant quantity in physics. To understand the concept of angular momentum first we need to understand a rigid body and its movement, a position vector that is used to specify the position of particles in space. A rigid body possesses motion it may be linear or rotational. Rotational motion plays important role in angular momentum.
Moment of a Force
The idea of moments is an important concept in physics. It arises from the fact that distance often plays an important part in the interaction of, or in determining the impact of forces on bodies. Moments are often described by their order [first, second, or higher order] based on the power to which the distance has to be raised to understand the phenomenon. Of particular note are the second-order moment of mass (Moment of Inertia) and moments of force.
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Q5) Kinetic Energy of Rotation and Rolling Motion
A m = 2kg ring has a radius of r = 0.5m. The moment of
inertia of a ring is I = m r2.
The ring has an initial speed of v = 1 m/s on the
horizontal surface. It rolls, without slipping, along the
surface and up the ramp, where it stops when it
reaches a height h.
a) What is the
b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring?
c) Use Conservation of Energy to find the maximum height of the ring, h.
Solve the problem using variables.
Only substitute numbers in the very last step
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