Macmillan Learning Your computer has an optical disk drive that can spin up to 10,000 rpm (which is about 1045 rad/s). If a certain disk is spun at 352.9 rad/s during the time it is being read, and then comes to rest over 0.569 seconds, what is the magnitude of the average angular acceleration of the disk? average angular acceleration: If the disk is 0.12 m in diameter, what is the magnitude of the linear acceleration of a point 1/3 of the way out from the center the disk? linear acceleration: x10 rad/s TOOLS m/s

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Chapter1: Units, Trigonometry. And Vectors
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**Educational Content on Angular and Linear Acceleration**

---

**Problem Statement:**

Your computer has an optical disk drive that can spin up to 10,000 rpm (which is about 1045 rad/s). If a certain disk is spun at 352.9 rad/s during the time it is being read, and then comes to rest over 0.569 seconds, what is the magnitude of the average angular acceleration of the disk?

- **Average Angular Acceleration:** _______ rad/s²

**Follow-up Question:**

If the disk is 0.12 m in diameter, what is the magnitude of the linear acceleration of a point 1/3 of the way out from the center of the disk?

- **Linear Acceleration:** _______ m/s²

**Additional Tools:**

- A calculator or computational tool might be required to solve for the angular and linear acceleration.

**Guidance:**

1. **Understanding Angular Acceleration:**
   - Angular acceleration (\(\alpha\)) can be calculated using the formula:
     \[
     \alpha = \frac{\Delta \omega}{\Delta t}
     \]
     where \(\Delta \omega\) is the change in angular velocity and \(\Delta t\) is the time taken for this change.

2. **Understanding Linear Acceleration:**
   - Linear acceleration (a) at a radius (r) from the center of rotation is given by:
     \[
     a = \alpha \times r
     \]
   - For this problem, calculate \(r = \frac{0.12 \, \text{m}}{2} \times \frac{1}{3}\) since the point is 1/3 of the way from the center.

**Tools Section:**

- The "Tools" dropdown might provide computational assistance, particularly for applying powers of ten in calculations (e.g., \(x10^y\)).

**Calculation Steps:**

1. Calculate \(\Delta \omega\) = \(-352.9 \, \text{rad/s}\) (since it comes to rest, final angular velocity is 0).
2. Divide by the time interval, \(\Delta t = 0.569 \, \text{s}\), to find \(\alpha\).
3. Use \(\alpha\) and the radius to find the linear acceleration of the specified point.

---
Transcribed Image Text:**Educational Content on Angular and Linear Acceleration** --- **Problem Statement:** Your computer has an optical disk drive that can spin up to 10,000 rpm (which is about 1045 rad/s). If a certain disk is spun at 352.9 rad/s during the time it is being read, and then comes to rest over 0.569 seconds, what is the magnitude of the average angular acceleration of the disk? - **Average Angular Acceleration:** _______ rad/s² **Follow-up Question:** If the disk is 0.12 m in diameter, what is the magnitude of the linear acceleration of a point 1/3 of the way out from the center of the disk? - **Linear Acceleration:** _______ m/s² **Additional Tools:** - A calculator or computational tool might be required to solve for the angular and linear acceleration. **Guidance:** 1. **Understanding Angular Acceleration:** - Angular acceleration (\(\alpha\)) can be calculated using the formula: \[ \alpha = \frac{\Delta \omega}{\Delta t} \] where \(\Delta \omega\) is the change in angular velocity and \(\Delta t\) is the time taken for this change. 2. **Understanding Linear Acceleration:** - Linear acceleration (a) at a radius (r) from the center of rotation is given by: \[ a = \alpha \times r \] - For this problem, calculate \(r = \frac{0.12 \, \text{m}}{2} \times \frac{1}{3}\) since the point is 1/3 of the way from the center. **Tools Section:** - The "Tools" dropdown might provide computational assistance, particularly for applying powers of ten in calculations (e.g., \(x10^y\)). **Calculation Steps:** 1. Calculate \(\Delta \omega\) = \(-352.9 \, \text{rad/s}\) (since it comes to rest, final angular velocity is 0). 2. Divide by the time interval, \(\Delta t = 0.569 \, \text{s}\), to find \(\alpha\). 3. Use \(\alpha\) and the radius to find the linear acceleration of the specified point. ---
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