A wheel has an angular speed of 49 rev/s when it experiences a constant angular acceleration of 69 rev/s² which causes it to spin FASTER. During this time the wheel completes 70 rev. Determine how long the wheel was experiencing this angular acceleration and how fast the wheel was spinning at the end of this period. Assume that the wheel doesn't change the direction of its spin. At = wf =
A wheel has an angular speed of 49 rev/s when it experiences a constant angular acceleration of 69 rev/s² which causes it to spin FASTER. During this time the wheel completes 70 rev. Determine how long the wheel was experiencing this angular acceleration and how fast the wheel was spinning at the end of this period. Assume that the wheel doesn't change the direction of its spin. At = wf =
College Physics
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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![**Problem Statement:**
A wheel has an angular speed of 49 revolutions per second (rev/s) when it experiences a constant angular acceleration of 69 revolutions per second squared (rev/s²), which causes it to spin faster. During this time, the wheel completes 70 revolutions. Determine how long the wheel was experiencing this angular acceleration and how fast the wheel was spinning at the end of this period. Assume that the wheel doesn't change the direction of its spin.
**Given:**
- Initial angular speed \( \omega_i = 49 \, \text{rev/s} \)
- Angular acceleration \( \alpha = 69 \, \text{rev/s}^2 \)
- Total revolutions \( \theta = 70 \, \text{rev} \)
**Required:**
1. Time duration \( \Delta t \) for the wheel to complete these revolutions.
2. Final angular speed \( \omega_f \).
**Equations:**
1. \( \theta = \omega_i \Delta t + \frac{1}{2} \alpha (\Delta t)^2 \)
2. \( \omega_f = \omega_i + \alpha \Delta t \)
You can solve these equations to find \( \Delta t \) and \( \omega_f \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F946aa72e-7881-4017-a582-113ad469f308%2F7ef1f292-208e-42a1-97b1-d6fe7980b958%2Fltxmar_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A wheel has an angular speed of 49 revolutions per second (rev/s) when it experiences a constant angular acceleration of 69 revolutions per second squared (rev/s²), which causes it to spin faster. During this time, the wheel completes 70 revolutions. Determine how long the wheel was experiencing this angular acceleration and how fast the wheel was spinning at the end of this period. Assume that the wheel doesn't change the direction of its spin.
**Given:**
- Initial angular speed \( \omega_i = 49 \, \text{rev/s} \)
- Angular acceleration \( \alpha = 69 \, \text{rev/s}^2 \)
- Total revolutions \( \theta = 70 \, \text{rev} \)
**Required:**
1. Time duration \( \Delta t \) for the wheel to complete these revolutions.
2. Final angular speed \( \omega_f \).
**Equations:**
1. \( \theta = \omega_i \Delta t + \frac{1}{2} \alpha (\Delta t)^2 \)
2. \( \omega_f = \omega_i + \alpha \Delta t \)
You can solve these equations to find \( \Delta t \) and \( \omega_f \).
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given data:
Initial Angular speed (ωi) = 49 rev/s
Angular acceleration (α) = 69 rev/s2
Angular displacement (Δθ) = 70 rev
Required:
Final angular velocity (ωf) and time interval (Δt)
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