Q2. The following particulars relate to a two row velocity compounded impulse wheelwhich forms a first stage of a combination turbine.Steam velocity at nozzle outlet = 579.12m/sMean blade velocity = 115.82m/sNozzle outlet angle = 16°Outlet angle first row of moving blades = 18°Outlet angle fixed guide blades = 22°Outlet angle, second row of moving blades = 36°Steam flow rate = 2.4 kg/sThe ratio of the relative velocity at outlet to that at inlet is 0.84 for all blades. Determinefor each row of moving blades the following⚫ The velocity of whirl• The tangential thrust on blades• The axial thrust on the blades• The power developedWhat is the efficiency of the wheel as a whole?

To solve this problem, we'll use the given data and calculate the required values for each row of…

Answered: Q2. The following particulars relate to…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The following data relate to a compound impulse turbine having two rows of moving blades and one row of fixed blades in between them. Steam velocity coming out of nozzle = 450 m/sec., Nozzle angle 15°, Moving blades tip discharge angles = 30°, Fixed blade discharge angle = 20°, Friction loss in each blade rows = 10% of the relative velocity. Find the blade velocity, blade efficiency and specific steam consumption for turbine.
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The following particular refer to a two row velocity compounded Impulse steam turbine (wheel). Steam velocity at Nozzle exit-600 m/sec, Nozzle angle - 16°, Mean Blade velocity = 120 m/sec. Exit angles; first row of moving blades - 18° Fixed guide blades = 22⁰ Second row of moving blades 36° Steam flow rate=5kg/sec. Blade friction coefficient=0.85 Determine (1) Tangential thrust
‘The following particulars refer to a two-row velocity-compounded impulse wheel which forms the frst stage of a combination turbine: Steam velocity at nozzle outlet :630 mis Mean blade velocity 125 mls Nozzle angle :16° Outlet angle, first row of moving blades 18 Outlet angle, fixed guide blades 1220 Outlet angle, second row of moving blades :36° Steam flow rate 26kgs ‘The ratio of the relative velocity at outlet to that at inlet is 0.84 for all the blade. Determine ) The velocity of whirl.
‘The following particulars refer to a two-row velocity-compounded impulse wheel which forms the frst stage of a combination turbine: Steam velocity at nozzle outlet :630 mis Mean blade velocity 125 mls Nozzle angle :16° Outlet angle, first row of moving blades 18 Outlet angle, fixed guide blades 1220 Outlet angle, second row of moving blades :36° Steam flow rate 26kgs ‘The ratio of the relative velocity at outlet to that at inlet is 0.84 for all the blade. Determine ) The velocity of whirl. (b) The tangential thrust on the blades.
‘The following particulars refer to a two-row velocity-compounded impulse wheel which forms the frst stage of a combination turbine: Steam velocity at nozzle outlet :630 mis Mean blade velocity 125 mls Nozzle angle :16° Outlet angle, first row of moving blades 18 Outlet angle, fixed guide blades 1220 Outlet angle, second row of moving blades :36° Steam flow rate 26kgs ‘The ratio of the relative velocity at outlet to that at inlet is 0.84 for all the blade. Determine ) The velocity of whirl. () The tangentia thrust on the blades () The axial thrust on the blades. (@) The power developed. (e) The blading efficiency.
Solve in 5 min
Using data given below, determine the main dimensions and blade angles of a Francis turbine. Net head=65 m, speed%3 700 rpm, BHP= 400. Actual hydraulic efficiency= 94%, overall efficiency= 85%, flow ratio= 0.18, wheel width at inlet/ wheel diameter at inlet=0.1, inner diameter/ outer diameter= 0.5. Assuming constant velocity of flow and radial discharge. Neglect area blocked by blades. Vane angle at inlet:
Q.4//in a single stage simple impulse turbine the steam flows at a rate of 5kg/s. It has rotor of 1.2m diameter running at 3000 rpm. Nozzle angle is 18°, blade speed ratio is 0.4 and velocity coefficient is 0.9, outlet angle of blade is 3° less than inlet angle. Determine blade angles and power developed.
A single jet Pelton wheel is required to drive a generator to develop 10Mw. The available head at the nozzle is 762m. Assuming electric generator efficiency is 95%, Pelton wheel efficiency 87%, coefficient of velocity 0.97, mean bucket velocity 0.46 of the jet velocity, outlet bucket angle 15° and the friction of bucket reduces the relative velocity by 15%, find (a) the flow rate of water through turbine (b) the diameter of the jet (c) the force exerted by the jet to the nozzle.
Using data given below, determine the main dimensions and blade angles of a Francis turbine. Net head=65 m, speed%3 700 rpm, BHP= 400. Actual hydraulic efficiency= 94%, overall efficiency= 85%, flow ratio= 0.18, (wheel width at inlet/ wheel diameter at inlet)=0.1, (inner diameter/ outer diameter)= 0.5, assuming constant velocity of flow and radial discharge. Neglect area blocked by blades. Width of the wheel at outlet:
6.9 One stage of an impulse turbine consists of a converging nozzle and one ring of moving blades. The nozzle angles are 22° and the blade angles are 35°. The velocity of steam at the exit from the nozzle is 650 m/s. If the relative velocity of steam to the blades is reduced by 14% in passing through the blade ring, find the diagram efficiency and the end thrust on the shaft when the blade ring develops 1650 kW. (79.2%, 449 N)

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