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- Ip Ep=40 V f = 60 Hz N₂= 20- N₁ = 120 Find the maximum flux om om = Find the magnitude of the induced secondary voltage Es Es = units + Is Es units If the coefficient of coupling (k)= 0.75, determine the magnitude of the induced secondary voltage Es Esk=0.75 = unitsplease answer in bond paper 2. A 20-kW, 230-V DC shunt generator has a voltage regulation of 7.5%. Find the terminal voltage at no-load.A 50 Hz CT has 20 primary turns and 60 secondary turns, on a core of cross section 8 cm2. The secondary current is 5 amp. The impedance of the burden and the secondary winding are together equal to 0.7 + j 0.4 ohm. The excitation current required in the primary current to produce the working flux with the secondary open circuit is 0.6 angle 45 amp. Calculate the flux density in the core and the ratio and phase errors.
- A three phase stator is shown below. The positive polarity of the currents is shown in the image. The windings are fed with the following balanced three phase currents: la-lmcos(wt) Ib-Imcos(wt-90°) Ic=Imcos(wt+90°) a) Where would you label the positive axes of all three phase windings in the image? b) Draw the magnetic field vectors produced by each single phase, and the total rotating magnetic field for wt = 0° and wt = 90° in the following figures. c) Is the rotating magnetic field clockwise or counter-clockwise?Please solve , last time i got wrong answerA magnetic circuit has a m.m.f. of 400 AT and a reluctance of 2 x 105 AT/Wb. The magnetic flux in the magnetic circuit is_ mWb. 6 X
- Question 43The dc armature resistance of delta-connected alternator measured across its two terminal is 0.8 ohm. The effective resistance per phase is?An Armature runs at 250 r.p.m. and generates an e.m.f. at 50 Hz. There are 216 slots each containing 5 conductors. The winding is distributed and full pitch. All the conductors of each phase are in series and flux per pole is 30 mWb which is sinusoidal distributed.Calculate the number of pole.
- D2. When a generator's full-load output voltage is the same as its no-load output voltage it is said to be a) under-compounded b) flat-compounded c) over-compounded d) none of the above D3. The output of an overcompounded DC generator can be lowered by use of a a) rheostat connected in series with the series field b) rheostat connected in parallel with the series field c) rheostat connected in parallel with the shunt field d) none of the above D4. When might it be desirable to use an overcompounded generator? a) never b) always c) to compensate for line loss d) when you need a higher no-load voltage than your full-load voltagePlease help i want urjent answer i am waitingFigure 1 shows an electric generator with 3 rotor windings as marked by a-1, b-2 and c-3. A permanent magnet is placed in the middle of the rotor with the rotational direction. The 3 rotor windings are connected through line to the three identical load resistors R₁, R₂ and R3 in Wye connection. The resulting currents in each line are la, lb and Ic. Design the generator-line-load connections, and propose the methodologies to construct 3-phase 3-wire connection. Use a diagram to justify your answers. D (0 N $1 Figure 1