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Q2 The molar conductivity of strong electrolyte at infinite dilution (A) equals: A) The slope of Am versus concentration graph according to Onsager equation. B) The slope of A versus the square root of concentration graph according to Oswald's law. C) The intercept of Am versus the square root of concentration graph according to Onsager equation. D) The intercept of Am versus concentration graph according to Oswald's law. 340.4 1214 ME ALE 2.8 4.4 6.00

Q2 The molar conductivity of strong electrolyte at infinite dilution (A) equals: A) The slope of Am versus concentration graph according to Onsager equation. B) The slope of A versus the square root of concentration graph according to Oswald's law. C) The intercept of Am versus the square root of concentration graph according to Onsager equation. D) The intercept of Am versus concentration graph according to Oswald's law. 340.4 1214 ME ALE 2.8 4.4 6.00

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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R-8,314 1/K.mol F-96485 N, 6.022x10 1 2 345 6 78 9 10 11 12 13 14 15 16 17 Q1. The conductivity of 0.02 M KCl solution at 25 °C is 2.768x10 S.cm The resistance of this solution at 25 C when measured with a particular cell was 250.2 02. The resistance of 0.01 NaCl at 25 C with the same cell was 200.0 2. Calculate the molar conductivity (Sem'mol) of the NaCl solution. A) 124.8 B) 346 3 C) 279 9 D) 456,3 E) 232.4 In order to find K., value for a weak acid (AB), three strong electrolytes (AC, NB and NC) were chosen. The graph aside is for AC electrolyte Q2 The molar conductivity of strong electrolyte at AC Strong Electrolyte infinite dilution (A) equals. A) The slope of Am versus concentration graph according to Onsager equation. B) The slope of A versus the square root of concentration graph according to Oswald's law. C) The intercept of Am versus the square root of concentration graph according to Onsager equation. D) The intercept of A versus concentration graph according to Oswald's law. 1818 340.4 1214 300.0 BLO ME 410 30.0 06 6.00 الأسم v-405.95x 183.31 -0.9473 das 8.10 8.15 x-variable Q3. The molar conductivity (Sem'mol") at infinite dilution for AC is A) 183.3 B) 406.5 C) 138.2 D) 380.1 Q4. If A-170 for NB, and A" 165.2 for NC, the molar conductivity at infinite dilutiofor AB is A) 178.3 6.10 B) 188.11 C) 150.87 D) 142.99 Based on the following plot that was obtained from the experiment of determining the dissociation constant of weak organic acid using conductivity measuremen Q5. Both molar conductivity at infinite dilution (A) and dissociation constant (K₂) for the acid can be determined by plotting.. VS..... A) 1/A vs. CAm B) Am vs. Vc. C) Am Vs. C D) CA, VS. VE Q6. The molar conductivity at infinite dilution (A) for the acid equals A) 213 B). 333 C) 786 D) 456 Q7. Calculate the equilibrium constant at 25 "C for the reaction 2Fe (aq) +2 (aq)-2 2Fe²(aq) + 1:(s) Given the standard reduction potentials: 2Fe +2e2Fe²+ E-0.771 V 1₂ +2e21 A) 18.31 E-0.5355 V B) 9.3 C) 9.10x10 D) 9.54x10' E) 2.9x10 Q8. In the reaction of hydrolysis of ethyl acetate in acid medium, the rate constant at 40°C is 12,6 s and at 80°C is 46.5 s. The activation energy (E) in kJ/mol is: C) 25.0 D) 29987 A) 25780 B) 30.0 09. In the iodination of acetone experiment, the reaction rate is followed through titration of 12 with 0.1 M SO.. If volume of 1₂ used for titration is 10 ml. A plot of V vst is constructed with the equation of line: Y-2.8 X. Determine the rate constant K D) 2.42 E) 0.642 A) 0.853 C) 0.014 B) 1.61 0.30 Yes.com 835
Transcribed Image Text:R-8,314 1/K.mol F-96485 N, 6.022x10 1 2 345 6 78 9 10 11 12 13 14 15 16 17 Q1. The conductivity of 0.02 M KCl solution at 25 °C is 2.768x10 S.cm The resistance of this solution at 25 C when measured with a particular cell was 250.2 02. The resistance of 0.01 NaCl at 25 C with the same cell was 200.0 2. Calculate the molar conductivity (Sem'mol) of the NaCl solution. A) 124.8 B) 346 3 C) 279 9 D) 456,3 E) 232.4 In order to find K., value for a weak acid (AB), three strong electrolytes (AC, NB and NC) were chosen. The graph aside is for AC electrolyte Q2 The molar conductivity of strong electrolyte at AC Strong Electrolyte infinite dilution (A) equals. A) The slope of Am versus concentration graph according to Onsager equation. B) The slope of A versus the square root of concentration graph according to Oswald's law. C) The intercept of Am versus the square root of concentration graph according to Onsager equation. D) The intercept of A versus concentration graph according to Oswald's law. 1818 340.4 1214 300.0 BLO ME 410 30.0 06 6.00 الأسم v-405.95x 183.31 -0.9473 das 8.10 8.15 x-variable Q3. The molar conductivity (Sem'mol") at infinite dilution for AC is A) 183.3 B) 406.5 C) 138.2 D) 380.1 Q4. If A-170 for NB, and A" 165.2 for NC, the molar conductivity at infinite dilutiofor AB is A) 178.3 6.10 B) 188.11 C) 150.87 D) 142.99 Based on the following plot that was obtained from the experiment of determining the dissociation constant of weak organic acid using conductivity measuremen Q5. Both molar conductivity at infinite dilution (A) and dissociation constant (K₂) for the acid can be determined by plotting.. VS..... A) 1/A vs. CAm B) Am vs. Vc. C) Am Vs. C D) CA, VS. VE Q6. The molar conductivity at infinite dilution (A) for the acid equals A) 213 B). 333 C) 786 D) 456 Q7. Calculate the equilibrium constant at 25 "C for the reaction 2Fe (aq) +2 (aq)-2 2Fe²(aq) + 1:(s) Given the standard reduction potentials: 2Fe +2e2Fe²+ E-0.771 V 1₂ +2e21 A) 18.31 E-0.5355 V B) 9.3 C) 9.10x10 D) 9.54x10' E) 2.9x10 Q8. In the reaction of hydrolysis of ethyl acetate in acid medium, the rate constant at 40°C is 12,6 s and at 80°C is 46.5 s. The activation energy (E) in kJ/mol is: C) 25.0 D) 29987 A) 25780 B) 30.0 09. In the iodination of acetone experiment, the reaction rate is followed through titration of 12 with 0.1 M SO.. If volume of 1₂ used for titration is 10 ml. A plot of V vst is constructed with the equation of line: Y-2.8 X. Determine the rate constant K D) 2.42 E) 0.642 A) 0.853 C) 0.014 B) 1.61 0.30 Yes.com 835
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