**Question Completion Status:** **QUESTION 1** For which of the following does \( K_C = K_P \) at the same temperature? - A. \( \text{CaCO}_3 (s) \rightleftharpoons \text{CaO} (s) + \text{CO}_2 (g) \) - B. \( \text{CO} (g) + \text{H}_2\text{O} (g) \rightleftharpoons \text{CO}_2 (g) + \text{H}_2 (g) \) - C. \( \text{N}_2 (g) + 3\text{H}_2 (g) \rightleftharpoons 2\text{NH}_3 (g) \) - D. \( 3\text{Fe} (s) + \text{H}_2\text{O} (g) \rightleftharpoons \text{Fe}_3\text{O}_4 (s) + 4\text{H}_2 (g) \) **QUESTION 2** When the following reaction is at equilibrium and the volume of the container is decreased, \[ \text{COCl}_2 (g) \rightleftharpoons \text{CO} (g) + \text{Cl}_2 (g) \] - A. the forward reaction rate increases. - B. the reverse reaction rate increases. - C. the reverse reaction rate decreases. - D. the equilibrium remains unchanged. - E. the forward reaction rate decreases. --- **Instructions:** Click Save and Submit to save and submit. Click Save All Answers to save all answers.
**Question Completion Status:** **QUESTION 1** For which of the following does \( K_C = K_P \) at the same temperature? - A. \( \text{CaCO}_3 (s) \rightleftharpoons \text{CaO} (s) + \text{CO}_2 (g) \) - B. \( \text{CO} (g) + \text{H}_2\text{O} (g) \rightleftharpoons \text{CO}_2 (g) + \text{H}_2 (g) \) - C. \( \text{N}_2 (g) + 3\text{H}_2 (g) \rightleftharpoons 2\text{NH}_3 (g) \) - D. \( 3\text{Fe} (s) + \text{H}_2\text{O} (g) \rightleftharpoons \text{Fe}_3\text{O}_4 (s) + 4\text{H}_2 (g) \) **QUESTION 2** When the following reaction is at equilibrium and the volume of the container is decreased, \[ \text{COCl}_2 (g) \rightleftharpoons \text{CO} (g) + \text{Cl}_2 (g) \] - A. the forward reaction rate increases. - B. the reverse reaction rate increases. - C. the reverse reaction rate decreases. - D. the equilibrium remains unchanged. - E. the forward reaction rate decreases. --- **Instructions:** Click Save and Submit to save and submit. Click Save All Answers to save all answers.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question Completion Status:**
**QUESTION 1**
For which of the following does \( K_C = K_P \) at the same temperature?
- A. \( \text{CaCO}_3 (s) \rightleftharpoons \text{CaO} (s) + \text{CO}_2 (g) \)
- B. \( \text{CO} (g) + \text{H}_2\text{O} (g) \rightleftharpoons \text{CO}_2 (g) + \text{H}_2 (g) \)
- C. \( \text{N}_2 (g) + 3\text{H}_2 (g) \rightleftharpoons 2\text{NH}_3 (g) \)
- D. \( 3\text{Fe} (s) + \text{H}_2\text{O} (g) \rightleftharpoons \text{Fe}_3\text{O}_4 (s) + 4\text{H}_2 (g) \)
**QUESTION 2**
When the following reaction is at equilibrium and the volume of the container is decreased,
\[ \text{COCl}_2 (g) \rightleftharpoons \text{CO} (g) + \text{Cl}_2 (g) \]
- A. the forward reaction rate increases.
- B. the reverse reaction rate increases.
- C. the reverse reaction rate decreases.
- D. the equilibrium remains unchanged.
- E. the forward reaction rate decreases.
---
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Transcribed Image Text:**Question Completion Status:**
**QUESTION 1**
For which of the following does \( K_C = K_P \) at the same temperature?
- A. \( \text{CaCO}_3 (s) \rightleftharpoons \text{CaO} (s) + \text{CO}_2 (g) \)
- B. \( \text{CO} (g) + \text{H}_2\text{O} (g) \rightleftharpoons \text{CO}_2 (g) + \text{H}_2 (g) \)
- C. \( \text{N}_2 (g) + 3\text{H}_2 (g) \rightleftharpoons 2\text{NH}_3 (g) \)
- D. \( 3\text{Fe} (s) + \text{H}_2\text{O} (g) \rightleftharpoons \text{Fe}_3\text{O}_4 (s) + 4\text{H}_2 (g) \)
**QUESTION 2**
When the following reaction is at equilibrium and the volume of the container is decreased,
\[ \text{COCl}_2 (g) \rightleftharpoons \text{CO} (g) + \text{Cl}_2 (g) \]
- A. the forward reaction rate increases.
- B. the reverse reaction rate increases.
- C. the reverse reaction rate decreases.
- D. the equilibrium remains unchanged.
- E. the forward reaction rate decreases.
---
**Instructions:**
Click Save and Submit to save and submit. Click Save All Answers to save all answers.
Expert Solution
Step 1
COCl2 -----> CO + Cl2
reactant has 1 mol and product side has 2 moles.
when volume of container is decreased, pressure increases. more number of moles will colloide more. and product side has more number of moles and they can colloide more and reverse reaction rate increases. equilibrium will shift to reactant side.
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