Q14. For the hypothesis test HO: µ =5 against H1: u>5 with unknown variance and n=15, approximate the P-value for each of the following test statistics of -1.05
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Q: For the hypothesis test Ho:μ = 5 against H₁:μ< 5 and variance known, calculate the P-value for the…
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- Q1: Suppose that Y,, Y2, Y constitute a random sample from a normal distribution with known mean u and unknown variance a?. The most powerful a-level test is sued for testing Ho:a² = o versus HA: 0² = af, where af > o3. نقطة واحدة .3 3. The rejection region is given by RR = A. True B. False10.29 Past experience indicates that the time required for high school seniors to complete a standardized test is a normal random variable with a mean of 35 minutes. If a random sample of 20 high school seniors took an average of 33.1 minutes to complete this test with a standard deviation of 4.3 minutes, test the hypothesis, at the 0.05 level of significance, that μ = 35 minutes against the alternative that μ < 35 minutes.Two suppliers manufacture a plastic gear used in a laser printer. The impact strength of these gears measured in foot-pounds is an important characteristic. A random sample of 10 gears from supplier 1 results in ₁ = 290 and s₁ = 12, and another random sample of 16 gears from the second supplier results in ₂ = 321 and s₂ = 22. Is there evidence to support the claim that supplier 2 provides gears with higher mean impact strength? Use a = 0.05, and assume that both populations are normally distributed but the variances are not equal. O a. Because -4.64 < -1.714, fail to reject the Null Hypothesis Ob. None among the choices O c. Reject the Null Hypothesis Od. Because -4.64 < -1.714, reject the Null Hypothesis
- A brochure inviting subscriptions for a new diet program states that the participants areexpected to lose over 27 pounds in five weeks. Suppose that, from the data of the five-weekweight losses of 65 participants, the sample mean and sample standard deviation are found tobe 21.5 and 3.4, respectively. Could the statement in the brochure be substantiated on thebasis of these findings? Test at the α = .01 level. Give detailed explanation with solution.A company is doing a hypothesis test on the variation of quality from two suppliers. Both distributions are normal, and the populations are independent. use a = 0.01 2 H0:01 HA: 01 > 2 2 02² 10₂² The standard deviation of the first sample is 2.2077 5.1485 is the standard deviation of the second sample. The test statistic is =A random sample of 23 bags of apples (marked as 10 pounds each) received by a large grocery chain tested out as having a mean of 9.2 pounds with a variance of 2.56 pounds. Test whether the true mean of all bags is under 10 pounds. Set up hypotheses. Perform the appropriate test by showing your formula. Interpret the results using a Type I (alpha) error of .05. Also provide the p value here. Also construct a 95% confidence interval around your sample mean (X bar) that should contain the true mean (mu). Also interpret this interval.
- The sample of 81 of pomegranates has a mean number f seed of 695, with a standard deviation of 300 seeds.Use this to test the claim that the average number of seeds in a pomegranate is 613,with s One Tailid.f.= 00 to.0o5 = 2.639, to.01= 2.374,to.085=1.990, Significance level of D.0a. %3D %3D8.36 Can we use the z test? In each of the following cases, state whether or not the Normal approximation to the binomial should be used for a significance test on the population proportion p. Explain your answers. (a) n = 30 and Ho: p = 0.3. (b) n = 60 and Ho: p = 0.2. (c) n = 100 and Ho: p = 0.12.The percentage of titanium in an alloy used in aerospace castings is measured in 51randomly selected parts. The sample standard deviation is σx̅= 0.37Test the hypothesis H0: σ = 0.25 versus Ha: σ ≠ 0.25 using α = 0.05.