Q11:-Gasoline (S=0.8) flows through Venturi-meter as shown in fig, if the actual discharge equal to 40 L/s and coefficient of discharge (Cd-0.96) calculate h? 150 mm 75 mm 150 mm Muhammad Gasoline Hg (s13.6)

Q11:-Gasoline (S=0.8) flows through Venturi-meter as shown in fig, if the actual discharge equal to 40 L/s and coefficient of discharge (Cd-0.96) calculate h? 150 mm 75 mm 150 mm Muhammad Gasoline Hg (s13.6)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Types of loading

In mechanical terminology, the term load indicates that external force/weight, either constant or variable, acts on a mechanical member/structure. The weight of an object of a specific material is also an external load, and the external force that works on a structure comes under the categories of loading. The external load generates its effects as stress and strain in the structure.

Question

Q11:-Gasoline (S=0.8) flows through Venturi-meter as shown in fig, if the actual
discharge equal to 40 L/s and coefficient of discharge (Cd-0.96) calculate h?
150 mm
75 mm
150 mm
Muhammad
Gasoline
Hg (s=13.6)

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Problem 5: Pipe Flow A 10,000 ft P BC 20,000 ft D This semester we worked through several versions of the pipe flow problem sketched above, in which a 3.0 ft diameter pipe is used to convey water from reservoir A (surface elevation 80 ft) to reservoir D (surface elevation 90 ft). In week 14, we considered a specific example with a cast iron pipe (A = 0.00085 ft), flow rate of Q=40 ft³/s, and average velocity of V = 5.66 ft/s. For these conditions, the friction factor was λ = 0.015 and the pump added 86 ft of head. Assume the water temperature is always 60°F. Part A Assuming the pump is 75% efficient and electricity costs 10e/kW.hr, how much will it cost to run this pump for a year? Hint, 1 kW hr = (1000 watts) (1 hr) = (1000 J/s)(3600 s) = 3.6x106 J. Part B Now let us assume we need to double the discharge to Q = 80 ft³/s, but unlike the example in week 13, we are not going to make the false assumption that the friction factor λ is constant. You may, however, assume that the roughness…