formula: Q.(V1)229h = 63.5cmtrial #1490mLtrialNo.DateDetermination of Discharge Thru a SiphonVol●Q=AVt )P1V2)2P2+71+2rY29trial #2trial #3+= 75t= 5sY = 340mlV: 250mLthe table below. I show calculation please)1TheoreticalActualDischargeDischarge(LIS)(L/₁)t = 10sV =complete++1time(s) Volume / H (m)(mL)++%Difference

Given Height = 83.5 cm To find Theoretical discharge Actual discharge Difference percentage

Answered: Determination of Discharge Thru a…

Engineering

Mechanical Engineering

Determination of Discharge Thru a Siphon

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Pressure Vessels

The term pressure vessel refers to a closed container that contains gas or liquid at a different pressure than environment pressure. The pressure vessels have a wide scale of applications in our day-to-day lives and other industrial places. Some common examples of pressure vessels are gas cylinders, autoclaves, compressor vessels, etc.

Question

formula: Q.
(V1)2
29
h = 63.5cm
trial #1
490mL
trial
No.
Date
Determination of Discharge Thru a Siphon
Vol
●
Q=AV
t )
P1
V2)2
P2
+71
+2
r
Y
29
trial #2
trial #3
+= 75
t= 5s
Y = 340ml
V: 250mL
the table below. I show calculation please)
1
Theoretical
Actual
Discharge
Discharge
(LIS)
(L/₁)
t = 10s
V =
complete
+
+
1
time(s) Volume / H (m)
(mL)
+
+
%
Difference

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