Pump head, hp, can be formulated as, h, = 22 - z1 + hm + he Where, E h = EK and hy = Table 1: Minor loss coefficients factor Loss Sharp entrance Open globe valve Open angle valve K 0.5 6.9 2.0 Bend 0.25 0.30 Regular 45° elbow Regular 90° elbow Half-opened gate valve Sharp exit 0.95 2.7 1.0 On this water pump piping system, you should perform the following analysis: a) Determine the velocity of water flowing in the pipe, V (unit in m/s. b) Determine the sum of minor loss coefficients. c) Calculate the Reynold number. d) By referring to the Moody's chart (or Colebrook formula), determine the pipe friction factor, f. e) Determine the pump head, h, (unit in meter). ) Compute the pump horsepower (hp) required, P = pgQh,. For unit conversion, 1 hp is equivalent to 745.7 watts. g) If the pump efficiency (n) is rated at 70%, from the theoretical value of pump horsepower output in (f), determine the actual pump input power required (hp).
Pump head, hp, can be formulated as, h, = 22 - z1 + hm + he Where, E h = EK and hy = Table 1: Minor loss coefficients factor Loss Sharp entrance Open globe valve Open angle valve K 0.5 6.9 2.0 Bend 0.25 0.30 Regular 45° elbow Regular 90° elbow Half-opened gate valve Sharp exit 0.95 2.7 1.0 On this water pump piping system, you should perform the following analysis: a) Determine the velocity of water flowing in the pipe, V (unit in m/s. b) Determine the sum of minor loss coefficients. c) Calculate the Reynold number. d) By referring to the Moody's chart (or Colebrook formula), determine the pipe friction factor, f. e) Determine the pump head, h, (unit in meter). ) Compute the pump horsepower (hp) required, P = pgQh,. For unit conversion, 1 hp is equivalent to 745.7 watts. g) If the pump efficiency (n) is rated at 70%, from the theoretical value of pump horsepower output in (f), determine the actual pump input power required (hp).
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:Pump head, h,, can be formulated as,
hp = z2 - 21 +
Where,
E h = EK and hy =4
Table 1: Minor loss coefficients factor
Loss
Sharp entrance
Open globe valve
Open angle valve
K
0.5
6.9
2.0
0.25
0.30
Bend
Regular 45° elbow
Regular 90° elbow
Half-opened gate valve
Sharp exit
0.95
2.7
1.0
On this water pump piping system, you should perform the following analysis:
a) Determine the velocity of water flowing in the pipe, V (unit in m/s.
b) Determine the sum of minor loss coefficients.
c) Calculate the Reynold number.
d) By referring to the Moody's chart (or Colebrook formula), determine the
pipe friction factor, f.
e) Determine the pump head, h, (unit in meter).
) Compute the pump horsepower (hp) required, P = pg̟hp. For unit
conversion, 1 hp is equivalent to 745.7 watts.
9) If the pump efficiency (n) is rated at 70%, from the theoretical value of
pump horsepower output in (f), determine the actual pump input power
required (hp).
Transcribed Image Text:B1) Water is pumped between two reservoirs, from point 1 (2, = 2 m) to point
2 (z, = 12 m), through a long pipe.
Screwed
Sharp
regular
90 elbow
esit
Sharp
Half-open
gate valve
entrance
bend
ripe
Pump
Open gkbe
alve
Figure 4: Water pump piping system
Given,
The density of water, p = 1000 kg/m
The dynamic viscosity of water, u = 1.485 x 10-3 kg/m.s
The flowrate of water, Q = 0.006 m²/s
The pipe roughness ratio, e/d = 0.001
The pipe diameter, d = 4 cm
The pipe length, L = 100 m
Va ci dater, in
Vo of
009 HLamin-
eeetfTransition-
Conplete atlece, gh pipes
Hool
Ho00
0.00
:0,008
H0.006
0,000
0.001
0.0006
C0,0006
0.0004
0.0001
0.000a5
Reyldh aher Re
-0.000
Figure 5: Moody chart
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