Pump head, h,, can be formulated as,hp = z2 - 21 +Where,E h = EK and hy =4Table 1: Minor loss coefficients factorLossSharp entranceOpen globe valveOpen angle valveK0.56.92.00.250.30BendRegular 45° elbowRegular 90° elbowHalf-opened gate valveSharp exit0.952.71.0On this water pump piping system, you should perform the following analysis:a) Determine the velocity of water flowing in the pipe, V (unit in m/s.b) Determine the sum of minor loss coefficients.c) Calculate the Reynold number.d) By referring to the Moody's chart (or Colebrook formula), determine thepipe friction factor, f.e) Determine the pump head, h, (unit in meter).) Compute the pump horsepower (hp) required, P = pg̟hp. For unitconversion, 1 hp is equivalent to 745.7 watts.9) If the pump efficiency (n) is rated at 70%, from the theoretical value ofpump horsepower output in (f), determine the actual pump input powerrequired (hp). B1) Water is pumped between two reservoirs, from point 1 (2, = 2 m) to point2 (z, = 12 m), through a long pipe.ScrewedSharpregular90 elbowesitSharpHalf-opengate valveentrancebendripePumpOpen gkbealveFigure 4: Water pump piping systemGiven,The density of water, p = 1000 kg/mThe dynamic viscosity of water, u = 1.485 x 10-3 kg/m.sThe flowrate of water, Q = 0.006 m²/sThe pipe roughness ratio, e/d = 0.001The pipe diameter, d = 4 cmThe pipe length, L = 100 mVa ci dater, inVo of009 HLamin-eeetfTransition-Conplete atlece, gh pipesHoolHo000.00:0,008H0.0060,0000.0010.0006C0,00060.00040.00010.000a5Reyldh aher Re-0.000Figure 5: Moody chart

a) Volume flow rate =0.006 m3/s ( given) Radius = 2cm = 0.02m Cross section area= 3.14 × 0.022…

Pump head, hp, can be formulated as, h, = 22 - z1 + hm + he Where, E h = EK and hy = Table 1: Minor loss coefficients factor Loss Sharp entrance Open globe valve Open angle valve K 0.5 6.9 2.0 Bend 0.25 0.30 Regular 45° elbow Regular 90° elbow Half-opened gate valve Sharp exit 0.95 2.7 1.0 On this water pump piping system, you should perform the following analysis: a) Determine the velocity of water flowing in the pipe, V (unit in m/s. b) Determine the sum of minor loss coefficients. c) Calculate the Reynold number. d) By referring to the Moody's chart (or Colebrook formula), determine the pipe friction factor, f. e) Determine the pump head, h, (unit in meter). ) Compute the pump horsepower (hp) required, P = pgQh,. For unit conversion, 1 hp is equivalent to 745.7 watts. g) If the pump efficiency (n) is rated at 70%, from the theoretical value of pump horsepower output in (f), determine the actual pump input power required (hp).

Pump head, hp, can be formulated as, h, = 22 - z1 + hm + he Where, E h = EK and hy = Table 1: Minor loss coefficients factor Loss Sharp entrance Open globe valve Open angle valve K 0.5 6.9 2.0 Bend 0.25 0.30 Regular 45° elbow Regular 90° elbow Half-opened gate valve Sharp exit 0.95 2.7 1.0 On this water pump piping system, you should perform the following analysis: a) Determine the velocity of water flowing in the pipe, V (unit in m/s. b) Determine the sum of minor loss coefficients. c) Calculate the Reynold number. d) By referring to the Moody's chart (or Colebrook formula), determine the pipe friction factor, f. e) Determine the pump head, h, (unit in meter). ) Compute the pump horsepower (hp) required, P = pgQh,. For unit conversion, 1 hp is equivalent to 745.7 watts. g) If the pump efficiency (n) is rated at 70%, from the theoretical value of pump horsepower output in (f), determine the actual pump input power required (hp).

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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