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This semester we worked through several versions of the pipe flow problem sketched above, in which a 3.0 ft diameter pipe is used to convey water from reservoir A (surface elevation 80 ft) to reservoir D (surface elevation 90 ft). In week 14, we considered a specific example with a cast iron pipe (A=0.00085 ft), flow rate of Q=40 ft/s, and average velocity of V=5.66 ftus. For these conditions, the friction factor was = 0.015 and the pump added 86 ft of head. Assume the water temperature is always 60°F. Part A Assuming the pump is 75% efficient and electricity costs 10e/kW.hr, how much will it cost to run this pump for a year? Hint, 1 kW hr = (1000 watts) (1 hr)= (1000 J/s)(3600 s) = 3.6x106 J. Part B Now let us assume we need to double the discharge to Q=80 ft³/s, but unlike the example in week 13, we are not going to make the false assumption that the friction factor is constant. You may, however, assume that the roughness height A is constant. We will consider three options: Option #1: Build a parallel system with the same pipe and pump, with a flow rate of Q = 40 ft³/s in each system. What is the annual electricity cost? Option #2: Use the original pipe but double the velocity. What is the annual electricity cost? Option # 3: Build a new pipe with diameter of 50.9 in. The cross-sectional area of this pipe is twice that of a 36 in pipe, so the velocity will be V=5.66 ft/s for a discharge of Q = 80 ft³/s. What is the annual electricity cost? Part C Briefly comment on the pros and cons of options 1-3 (<30 words).

This semester we worked through several versions of the pipe flow problem sketched above, in which a 3.0 ft diameter pipe is used to convey water from reservoir A (surface elevation 80 ft) to reservoir D (surface elevation 90 ft). In week 14, we considered a specific example with a cast iron pipe (A=0.00085 ft), flow rate of Q=40 ft/s, and average velocity of V=5.66 ftus. For these conditions, the friction factor was = 0.015 and the pump added 86 ft of head. Assume the water temperature is always 60°F. Part A Assuming the pump is 75% efficient and electricity costs 10e/kW.hr, how much will it cost to run this pump for a year? Hint, 1 kW hr = (1000 watts) (1 hr)= (1000 J/s)(3600 s) = 3.6x106 J. Part B Now let us assume we need to double the discharge to Q=80 ft³/s, but unlike the example in week 13, we are not going to make the false assumption that the friction factor is constant. You may, however, assume that the roughness height A is constant. We will consider three options: Option #1: Build a parallel system with the same pipe and pump, with a flow rate of Q = 40 ft³/s in each system. What is the annual electricity cost? Option #2: Use the original pipe but double the velocity. What is the annual electricity cost? Option # 3: Build a new pipe with diameter of 50.9 in. The cross-sectional area of this pipe is twice that of a 36 in pipe, so the velocity will be V=5.66 ft/s for a discharge of Q = 80 ft³/s. What is the annual electricity cost? Part C Briefly comment on the pros and cons of options 1-3 (<30 words).

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Problem 5: Pipe Flow A 10,000 ft P BC 20,000 ft D This semester we worked through several versions of the pipe flow problem sketched above, in which a 3.0 ft diameter pipe is used to convey water from reservoir A (surface elevation 80 ft) to reservoir D (surface elevation 90 ft). In week 14, we considered a specific example with a cast iron pipe (A = 0.00085 ft), flow rate of Q=40 ft³/s, and average velocity of V = 5.66 ft/s. For these conditions, the friction factor was λ = 0.015 and the pump added 86 ft of head. Assume the water temperature is always 60°F. Part A Assuming the pump is 75% efficient and electricity costs 10e/kW.hr, how much will it cost to run this pump for a year? Hint, 1 kW hr = (1000 watts) (1 hr) = (1000 J/s)(3600 s) = 3.6x106 J. Part B Now let us assume we need to double the discharge to Q = 80 ft³/s, but unlike the example in week 13, we are not going to make the false assumption that the friction factor λ is constant. You may, however, assume that the roughness height A is constant. We will consider three options: Option #1: Build a parallel system with the same pipe and pump, with a flow rate of Q=40 ft³/s in each system. What is the annual electricity cost? Option #2: Use the original pipe but double the velocity. What is the annual electricity cost? Option #3: Build a new pipe with diameter of 50.9 in. The cross-sectional area of this pipe is twice that of a 36 in pipe, so the velocity will be V=5.66 ft/s for a discharge of Q = 80 ft³/s. What is the annual electricity cost? Part C Briefly comment on the pros and cons of options 1-3 (<30 words).
Transcribed Image Text:Problem 5: Pipe Flow A 10,000 ft P BC 20,000 ft D This semester we worked through several versions of the pipe flow problem sketched above, in which a 3.0 ft diameter pipe is used to convey water from reservoir A (surface elevation 80 ft) to reservoir D (surface elevation 90 ft). In week 14, we considered a specific example with a cast iron pipe (A = 0.00085 ft), flow rate of Q=40 ft³/s, and average velocity of V = 5.66 ft/s. For these conditions, the friction factor was λ = 0.015 and the pump added 86 ft of head. Assume the water temperature is always 60°F. Part A Assuming the pump is 75% efficient and electricity costs 10e/kW.hr, how much will it cost to run this pump for a year? Hint, 1 kW hr = (1000 watts) (1 hr) = (1000 J/s)(3600 s) = 3.6x106 J. Part B Now let us assume we need to double the discharge to Q = 80 ft³/s, but unlike the example in week 13, we are not going to make the false assumption that the friction factor λ is constant. You may, however, assume that the roughness height A is constant. We will consider three options: Option #1: Build a parallel system with the same pipe and pump, with a flow rate of Q=40 ft³/s in each system. What is the annual electricity cost? Option #2: Use the original pipe but double the velocity. What is the annual electricity cost? Option #3: Build a new pipe with diameter of 50.9 in. The cross-sectional area of this pipe is twice that of a 36 in pipe, so the velocity will be V=5.66 ft/s for a discharge of Q = 80 ft³/s. What is the annual electricity cost? Part C Briefly comment on the pros and cons of options 1-3 (<30 words).
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