} Q1 ( shown. " The stresses in a bracket were obtained from a 3D finite element analysis as [20 0 15 (a) [A] = 0 10 25 L15 25 -30] (c) [₁] = (e) [σA] = -20 0 15 0 -10 -25 -25-30 15 20 20 0 -15] 0 10 25 -15 25 -30] 30 15 15 Which of the following stress tensors [A] correctly corresponds to the stress state at point A, as represented by the infinitesimal cube above. (All units in MPa.) 25 25 y₂ 10 (f) [σA] = X (b) [A] = 15 0 [20 15 0 10 -25 -25-30 [20 0 (d) [₁] = 0 10 L15 -25 15 -25 -30 -20 -15] 0 0 -10 -25 l-15 -25 -30]

} Q1 ( shown. " The stresses in a bracket were obtained from a 3D finite element analysis as [20 0 15 (a) [A] = 0 10 25 L15 25 -30] (c) [₁] = (e) [σA] = -20 0 15 0 -10 -25 -25-30 15 20 20 0 -15] 0 10 25 -15 25 -30] 30 15 15 Which of the following stress tensors [A] correctly corresponds to the stress state at point A, as represented by the infinitesimal cube above. (All units in MPa.) 25 25 y₂ 10 (f) [σA] = X (b) [A] = 15 0 [20 15 0 10 -25 -25-30 [20 0 (d) [₁] = 0 10 L15 -25 15 -25 -30 -20 -15] 0 0 -10 -25 l-15 -25 -30]

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Stress transformation

The term stress indicates the measure of internal forces that develop due to an external force's application on an object. When a specific external force is applied to an object, internal stress generates in the material. The value of stress can obtain by taking the ratio of the externally applied force and cross-sectional area of the object. There are different types of stress depending on the type of external force.

Question

Q1 (
shown.
* The stresses in a bracket were obtained from a 3D finite element analysis as
(a) [A] = 0
(c) [σA] =
[20 0 15
(e) [σA] =
Which of the following stress tensors [A] correctly corresponds to the stress state at point
A, as represented by the infinitesimal cube above. (All units in MPa.)
10 25
L15 25 -30]
[-20 0 15
0 -10 -25
15 -25 -30
20
20
0 -15]
0
10
25
-15 25 -30]
30
15
25 25
Y
[20 15 0
10
-25
-25
-30.
(b) [A] = 15
LO
(f) [A] =
[20
(d) [A] = 0
L15
0 15
10
-25
-25
-30]
OH O
0
[-20
-15]
0
-25
-15 -25 -30]
-10

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