**Problem Statement:**Find the total deformation of the aluminum bar system due to loading. (Unit: m)Given:- \( E_A = 73 \text{ GPa} \)- Cross-sectional area of member AB = \( 25 \text{ mm}^2 \)- Cross-sectional area of member BC = \( 75 \text{ mm}^2 \)**Diagram Description:**The diagram shows a horizontal bar system composed of two segments, AB and BC. - Segment AB measures 1.11 cm in length from point A to point B, and it is subjected to a force of 37.1 kN, directed to the left. - Segment BC measures 17.0 cm in length from point B to point C, with a force of 21.5 kN directed to the right.This setup illustrates the forces acting on the aluminum bar members and provides the necessary dimensions and forces for calculating the total deformation of the bar system.

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Find the total deformation of the aluminum (E₁ = 73 GPa) bar Syste due to loading ? (unit m) Criven: cross-sectional area member AB = 25 mm² and that of member BC = 75mm² A B 1.11 [cm] 37.1 [kN] 17.0 [cm] 21.5 [kN] C

Find the total deformation of the aluminum (E₁ = 73 GPa) bar Syste due to loading ? (unit m) Criven: cross-sectional area member AB = 25 mm² and that of member BC = 75mm² A B 1.11 [cm] 37.1 [kN] 17.0 [cm] 21.5 [kN] C

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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