J Criven tus, of consist of a steel ( Es = 200 CPd Ag = 1500 mm Assembly a brass ( E₂= 100 GPa plane B 75 AB= 2000 mm. 2) rod BC apply the 400k & load and is assumed rigid. + used to ²) Kod AB and " Find reactionary force at A, C ? Katus2-2201) NSU SOME OF
J Criven tus, of consist of a steel ( Es = 200 CPd Ag = 1500 mm Assembly a brass ( E₂= 100 GPa plane B 75 AB= 2000 mm. 2) rod BC apply the 400k & load and is assumed rigid. + used to ²) Kod AB and " Find reactionary force at A, C ? Katus2-2201) NSU SOME OF
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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
Transcribed Image Text:### Problem Statement
Given:
The assembly consists of a steel rod \( AB \) and a brass rod \( BC \). The properties of these materials are as follows:
- **Steel:**
- Modulus of Elasticity (\( E_s \)) = 200 GPa
- Cross-sectional Area (\( A_s \)) = 1500 mm²
- **Brass:**
- Modulus of Elasticity (\( E_b \)) = 100 GPa
- Cross-sectional Area (\( A_b \)) = 2000 mm²
Point \( B \) is used to apply a 400 kN load and is assumed to be rigid.
**Objective:**
Find the reactionary forces at points \( A \) and \( C \).
### Diagram Explanation
- The diagram shows a linear assembly consisting of two segments:
- **Segment \( AB\):** Made of steel. It is 1.500 m long and is subjected to a force of 200 kN at both ends.
- **Segment \( BC\):** Made of brass. It is 1.000 m long.
- **Forces:**
- A 200 kN force is applied at the left end \( A \).
- Another 200 kN force is applied to the right of point \( B \) at the beginning of brass rod \( BC \).
- The assembly undergoes a total external load of 400 kN applied at a rigid plate at point \( B \).
- **Support Points:**
- The reactions are required at points \( A \) and \( C \).
By solving this problem, you can determine the reactionary forces at the ends of the assembly, which is a common task in the analysis of statically determinate structures.
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