J Criven tus, of consist of a steel ( Es = 200 CPd Ag = 1500 mm Assembly a brass ( E₂= 100 GPa plane B 75 AB= 2000 mm. 2) rod BC apply the 400k & load and is assumed rigid. + used to ²) Kod AB and " Find reactionary force at A, C ? Katus2-2201) NSU SOME OF

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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### Problem Statement

Given:

The assembly consists of a steel rod \( AB \) and a brass rod \( BC \). The properties of these materials are as follows:

- **Steel:** 
  - Modulus of Elasticity (\( E_s \)) = 200 GPa
  - Cross-sectional Area (\( A_s \)) = 1500 mm²

- **Brass:** 
  - Modulus of Elasticity (\( E_b \)) = 100 GPa
  - Cross-sectional Area (\( A_b \)) = 2000 mm²

Point \( B \) is used to apply a 400 kN load and is assumed to be rigid.

**Objective:**

Find the reactionary forces at points \( A \) and \( C \).

### Diagram Explanation

- The diagram shows a linear assembly consisting of two segments:
  - **Segment \( AB\):** Made of steel. It is 1.500 m long and is subjected to a force of 200 kN at both ends.
  - **Segment \( BC\):** Made of brass. It is 1.000 m long. 

- **Forces:**
  - A 200 kN force is applied at the left end \( A \).
  - Another 200 kN force is applied to the right of point \( B \) at the beginning of brass rod \( BC \).
  - The assembly undergoes a total external load of 400 kN applied at a rigid plate at point \( B \).

- **Support Points:**
  - The reactions are required at points \( A \) and \( C \).

By solving this problem, you can determine the reactionary forces at the ends of the assembly, which is a common task in the analysis of statically determinate structures.
Transcribed Image Text:### Problem Statement Given: The assembly consists of a steel rod \( AB \) and a brass rod \( BC \). The properties of these materials are as follows: - **Steel:** - Modulus of Elasticity (\( E_s \)) = 200 GPa - Cross-sectional Area (\( A_s \)) = 1500 mm² - **Brass:** - Modulus of Elasticity (\( E_b \)) = 100 GPa - Cross-sectional Area (\( A_b \)) = 2000 mm² Point \( B \) is used to apply a 400 kN load and is assumed to be rigid. **Objective:** Find the reactionary forces at points \( A \) and \( C \). ### Diagram Explanation - The diagram shows a linear assembly consisting of two segments: - **Segment \( AB\):** Made of steel. It is 1.500 m long and is subjected to a force of 200 kN at both ends. - **Segment \( BC\):** Made of brass. It is 1.000 m long. - **Forces:** - A 200 kN force is applied at the left end \( A \). - Another 200 kN force is applied to the right of point \( B \) at the beginning of brass rod \( BC \). - The assembly undergoes a total external load of 400 kN applied at a rigid plate at point \( B \). - **Support Points:** - The reactions are required at points \( A \) and \( C \). By solving this problem, you can determine the reactionary forces at the ends of the assembly, which is a common task in the analysis of statically determinate structures.
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