The same element (as per previous question) is considered here again. Suppose that J11 J12] the Jacobian matrix can be written in the form of J = J21 J22. value of J21 for a point located at (§, n)=(-0.05,-0.50). (Hint: round you final answer to 4 digits after decimal point). y. 4 (1,6) 1 (0, 0) 2 (3, 2) 3 (5,5) X Find the
The same element (as per previous question) is considered here again. Suppose that J11 J12] the Jacobian matrix can be written in the form of J = J21 J22. value of J21 for a point located at (§, n)=(-0.05,-0.50). (Hint: round you final answer to 4 digits after decimal point). y. 4 (1,6) 1 (0, 0) 2 (3, 2) 3 (5,5) X Find the
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![The same element (as per previous question) is considered here again. Suppose that
[J11 J12]
the Jacobian matrix can be written in the form of J
=
J21 J22
value of J21 for a point located at (§, n)-(-0.05,-0.50). (Hint: round you final
answer to 4 digits after decimal point).
y
4 (1,6)
1 (0, 0)
2 (3, 2)
3 (5,5)
Find the
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F34ebf6bb-9266-4f57-a612-075806e7e349%2Fcb587d45-0e21-45bb-b664-806040ab2b2e%2Fl2pzci7_processed.png&w=3840&q=75)
Transcribed Image Text:The same element (as per previous question) is considered here again. Suppose that
[J11 J12]
the Jacobian matrix can be written in the form of J
=
J21 J22
value of J21 for a point located at (§, n)-(-0.05,-0.50). (Hint: round you final
answer to 4 digits after decimal point).
y
4 (1,6)
1 (0, 0)
2 (3, 2)
3 (5,5)
Find the
X
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