@AB=4 rad/s. AB= 6 rad/s2 A 0.5 m TB/IC 1 m 60° KIC Now let's look closer at Figure 2 from the prior question. By drawing lines that pass through points B and C which are perpendicular to their velocities (the red lines in the figure above) we can locate the IC at the intersection (the star). Now we can use some basic trig to figure out the distance rB/Ic labeled in the figure, which is the radial distance from the IC to point B. I've drawn in a green dashed line that creates two right triangles to help with the trig. What is the distance TB/IC? Give your answer in m but don't type the unit.
@AB=4 rad/s. AB= 6 rad/s2 A 0.5 m TB/IC 1 m 60° KIC Now let's look closer at Figure 2 from the prior question. By drawing lines that pass through points B and C which are perpendicular to their velocities (the red lines in the figure above) we can locate the IC at the intersection (the star). Now we can use some basic trig to figure out the distance rB/Ic labeled in the figure, which is the radial distance from the IC to point B. I've drawn in a green dashed line that creates two right triangles to help with the trig. What is the distance TB/IC? Give your answer in m but don't type the unit.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:@AB = 4 rad/s
%AB = 6 rad/s²
0.5 m
45°
B/C
1 m
60°
IC
Now let's look closer at Figure 2 from the prior question. By drawing lines that pass through
points B and C which are perpendicular to their velocities (the red lines in the figure above)
we can locate the IC at the intersection (the star). Now we can use some basic trig to figure
out the distance TB/Ic labeled in the figure, which is the radial distance from the IC to point B.
I've drawn in a green dashed line that creates two right triangles to help with the trig. What is
the distance TB/IC? Give your answer in m but don't type the unit.
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