### Text Transcription**Given:**- \( E_s = 200 \, \text{GPa} \)- \( A_1 = 200 \, \text{mm}^2 \)- \( A_2 = 400 \, \text{mm}^2 \)- Point C lies 0.725 m from pin at point A and point D lies 2.625 m from wall at B.**Problem:**Find the reactionary force at B in the x-direction. (Units in kN)### Diagram ExplanationThe diagram is a horizontal bar supported at both ends with forces applied at two points along its length.1. **Structure:** - The bar has points labeled from left to right as A, C, D, B. - A pin supports the bar at point A, and a wall fixes the bar at point B.2. **Measurements:** - The distance from point A to C is 1.45 meters. - The distance from point C to point D is implicit from the total length. - The total distance from point A to B is 5.250 meters.3. **Forces:** - A force of 19.0 kN acts to the right at point C. - A force of 65.0 kN acts to the right at point D.4. **Cross-sectional Areas:** - \( A_1 = 200 \, \text{mm}^2 \) near A - \( A_2 = 400 \, \text{mm}^2 \) near B### TaskDetermine the horizontal reactionary force at point B due to the applied loads on the bar. The result is expressed in kilonewtons (kN).

Answered: Image /qna-images/answer/27745cd9-e953-4a0e-aebe-e9b52e530bac.jpg

E₁ = 200GP₁₁ A₁ = 200 mm ² A 1.45 [m] 2 A = 400 mm ² C T point A and point D lies 2.625 m from wall at B. Find the reactionary force at B in x-direction. (UNIT KN) . A₁ 19.0 [kN] 4₂ E Point C les 0.725 m. 5.250 [m] De from pin at 65.0 [kN] B

E₁ = 200GP₁₁ A₁ = 200 mm ² A 1.45 [m] 2 A = 400 mm ² C T point A and point D lies 2.625 m from wall at B. Find the reactionary force at B in x-direction. (UNIT KN) . A₁ 19.0 [kN] 4₂ E Point C les 0.725 m. 5.250 [m] De from pin at 65.0 [kN] B

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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