Q1 MIPS single-cycle CPUMemtoRegMemWriteControlUnitBranchALUControl20ALUSrcFunct RegDstPCSrc31:26Op5:0RegWriteCLKCLKCLK25 21WE3SrcAZeroV WEA1RD1PC'PCARD InstrReadDataRDALUResultAInstruction20:16A2RD2OSrcBDataMemoryАЗMemoryWD3 RegisterFileWriteDataWD20:1615:11WriteReg.oPCPlus4Signlmm<<215:0Sign ExtendPCBranchResultQ1.1 lw instruction execution.With the given MIPS single-cycle CPU schematic, when Iw $8, 4($9) is executed, select all thecrrect answers below:O ALUSrc MUST be 1O WriteData bus has the value of $8Branch might be 1O RegWrite might be 0ORegDst MUST be 1O MemtoReg MUST be 0O SrcA has the value of $9O SrcB has the value from $8O MemWrite MUST be 1Provide your explanations for each of the options (why it is correct or incorrect).Enter your answer here

Solution:-- 1)The given question is related with an multiple choice question in which it is…

Answered: Q1 MIPS single-cycle CPU MemtoReg…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Yes Is next No instruction MAR E PC No memory IBR2 access required MBR + MOMAR Yes BR E MERN9) IR E MBR(0:7) MAR E MBR(8:19) |No Left IR E IBR (0:7) MAR E IBR (8:19) IR E MBR(20.27) MAR + MBR(28:39) instruction eguireg PC + PC+1 Memor Left instruction Right instruction y location LOAD M(300) SUB M(301) LOAD MQ , M(302) STOR M(303) STOR M(304) 100 101 STOR M(305) MULT M(305) LOAD MQ 102 103 104 HALT 300 301 302 303 304 305 Suppose you start your program from Memory location 100, and we execute the instruction with program counter is 103. What is the content of IBR? FETCH CYCLE
8
Base on the image provided below, write down a pair of equivalent mnemonic opcode/operand instructions that best describes the register indirect addressing mode. Remember that the data is distributed according to the Little Endian format. REGISTER INDIRECT ADDRESSING MEMORY Data Address EAX 34 12 3412 34 02002 EBX 10 00 1000H +. 12 02000 2000H 1B 020FE A2 020FC DS 0100 X10 АВ 01000 100 01000H MOV AX, [BX] or MOV AX, DS:[BX] а. O b. MOV AX, [CX] or MOV AX, DS:[CX] O c. MOV AX, [BX] or MOV AX, [DS:BX] O d. MOV AX, [BX] or MOV AX, SS:[BX]
Write ike micro-cperations for the execute cycles of the following registe. -ieference instructions. Instruction Hexadecimal Definition Symbol Code CLA 7800 Clear Accumulator Clear E register Complement Accumulator Complement E register CLE 7400 CMA 7200 CME 7100 INC 7020 Increment Accumulator HLT 7001 Halt Computer
If short JMP instruction reside in memory location 02001 what is the ?address of next instruction 02002 O 02003 O 02001 O none of them O
Indirect Addressing Mode Instruction 002A J@ RETADR 3E20030030 RETADR RESW 1 1.Instruction Starts with 002A2.Opcode of J is 3C3.Object code is 3E2003Please show the details
Assemble the following Marie program giving hexadecimal locations, label table, and machine commands. Loc Label OpCode Operand Command 100 Org 100 100 Start, Input SkipCond 000 SkipCond 800 Halt Output Store Max Loop, Input Add Sum Store Sum Output Sub Max SkipCond 800 Jump Loop Clear Store Sum Jump Start Sum, Dec 000 Max, Dec 050 End Start Label Table: Location Label Comments
Given the instruction set for MARIE: Instruction Opcode Instruction Opcode 0 1 2 3 4 5 6 Add 00F Instruction JnS X Load X Store X Addl OOF Add X Subt X Input Output What is the assembly language equivalent for the machine instruction: 1011 000000001111. Skipcond OOF Clear 7 8 9 A B C Instruction Halt Skipcond (00 for AC0) Jump X Clear Addl X Jumpl X
A memory cell contains the byte: 11011000 * O The highest significant bit is 1, The lowest significant bit is 1 O The lowest significant bit is 1, The highest significant bit is 0 O The highest significant bit is 1, The lowest significant bit is 0 O The lowest significant bit is 0, The lowest significant bit is 0 The instruction register is used to * Hold the instruction being executed All of the above Hold the memory address of the next instruction Hold input of the arithmetic units
Encode the following Y86-64 instructions: 1. addq %rbx, %rdx 2. irmovq $0xdcba, %rax 3. mrmovq-12(%rbp), %rcx
Microprocessor 8086

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