Problem 2. For each of the following assembly code sequences, say what value ends up in %rax at the end of the sequence of instructions. Assume the starting state is what was given for the previous problem. a. b. C. movq (%rdi), %rax movq (%rax), %rax movq (%rax), %rax movq (%rax), %rax addq %rcx, %rax movq (%rdi, %rdx), %rax movq (%rdi, %rdx, 4), %rbx shlq $3, %rbx addq rbx, rax movq 56(%rdi), rbx movq 8(%rdi), %rcx subq %rbx, %rcx leaq (%rcx,%rbx, 2), %rax 3
Problem 2. For each of the following assembly code sequences, say what value ends up in %rax at the end of the sequence of instructions. Assume the starting state is what was given for the previous problem. a. b. C. movq (%rdi), %rax movq (%rax), %rax movq (%rax), %rax movq (%rax), %rax addq %rcx, %rax movq (%rdi, %rdx), %rax movq (%rdi, %rdx, 4), %rbx shlq $3, %rbx addq rbx, rax movq 56(%rdi), rbx movq 8(%rdi), %rcx subq %rbx, %rcx leaq (%rcx,%rbx, 2), %rax 3
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Using the chart provided in the second image, solve problem 2
![Problem 2. For each of the following assembly code sequences, say what value ends up in %rax at
the end of the sequence of instructions. Assume the starting state is what was given for the previous
problem.
a.
b.
C.
movq (%rdi), %rax
movq (%rax), %rax
movq (%rax), %rax
movq (%rax), %rax
addq %rcx, %rax
movq (%rdi, %rdx), %rax
movq (%rdi,%rdx, 4), %rbx
shlq $3, %rbx
addq rbx, rax
movq 56(%rdi), rbx
movq 8(%rdi), %rcx
subq %rbx, %rcx
leaq (%rcx, %rbx, 2), %rax
3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2b0246-74c5-427f-bbae-6a253749f017%2F0caf3374-fcdc-4616-9dea-e616596cd45c%2F3pba8f_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 2. For each of the following assembly code sequences, say what value ends up in %rax at
the end of the sequence of instructions. Assume the starting state is what was given for the previous
problem.
a.
b.
C.
movq (%rdi), %rax
movq (%rax), %rax
movq (%rax), %rax
movq (%rax), %rax
addq %rcx, %rax
movq (%rdi, %rdx), %rax
movq (%rdi,%rdx, 4), %rbx
shlq $3, %rbx
addq rbx, rax
movq 56(%rdi), rbx
movq 8(%rdi), %rcx
subq %rbx, %rcx
leaq (%rcx, %rbx, 2), %rax
3
![Address Memory Contents
0x10040
0x10038
0x10030
0x10028
0x10020
0x10018
0x10010
0x10008
0x10000
100
0x10040
200
25
0x10028
0x10020
500
0x10018
2
Register Contents
%rdi
0x10008
%rsi
0x20
%rdx
%rcx
8
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2b0246-74c5-427f-bbae-6a253749f017%2F0caf3374-fcdc-4616-9dea-e616596cd45c%2F06tup5c_processed.png&w=3840&q=75)
Transcribed Image Text:Address Memory Contents
0x10040
0x10038
0x10030
0x10028
0x10020
0x10018
0x10010
0x10008
0x10000
100
0x10040
200
25
0x10028
0x10020
500
0x10018
2
Register Contents
%rdi
0x10008
%rsi
0x20
%rdx
%rcx
8
4
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