y = (ax + b)√ax + b

Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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The equation presented is:

\[ y = (ax + b)\sqrt{ax + b} \]

This mathematical expression describes a function \( y \) that is a product of a linear term and the square root of that same linear term. Here's a breakdown of the components of this function:

- \( a \) and \( b \) are constants.
- \( x \) is the independent variable.
- \( y \) is the dependent variable.

### Explanation

The expression \( (ax + b)\sqrt{ax + b} \) can be interpreted as follows:

1. Begin with the linear term \( ax + b \).
2. Multiply this linear term by its own square root, \( \sqrt{ax + b} \).

This type of expression might come up in contexts involving algebraic manipulations, functions, and mathematical modeling where compound growth or transformations are involved.

### Example

Suppose \( a = 1 \) and \( b = 2 \), the function simplifies to:

\[ y = (x + 2)\sqrt{x + 2} \]

This form of function can exhibit interesting behavior and is useful for demonstrating specific algebraic properties or for solving particular problems in calculus.
Transcribed Image Text:The equation presented is: \[ y = (ax + b)\sqrt{ax + b} \] This mathematical expression describes a function \( y \) that is a product of a linear term and the square root of that same linear term. Here's a breakdown of the components of this function: - \( a \) and \( b \) are constants. - \( x \) is the independent variable. - \( y \) is the dependent variable. ### Explanation The expression \( (ax + b)\sqrt{ax + b} \) can be interpreted as follows: 1. Begin with the linear term \( ax + b \). 2. Multiply this linear term by its own square root, \( \sqrt{ax + b} \). This type of expression might come up in contexts involving algebraic manipulations, functions, and mathematical modeling where compound growth or transformations are involved. ### Example Suppose \( a = 1 \) and \( b = 2 \), the function simplifies to: \[ y = (x + 2)\sqrt{x + 2} \] This form of function can exhibit interesting behavior and is useful for demonstrating specific algebraic properties or for solving particular problems in calculus.
### Instructions for Finding the Derivative

Find the derivative of the given function. You are **not required** to combine like terms, reduce fractions, or otherwise simplify your final answer. The symbols \( a \) and \( b \) are constants greater than 1.

---

This instruction appears on an educational website to guide students on how to find the derivative of a given function, emphasizing that simplification of the final answer is not necessary. Constants \( a \) and \( b \) are specified to be greater than 1 for clarity.
Transcribed Image Text:### Instructions for Finding the Derivative Find the derivative of the given function. You are **not required** to combine like terms, reduce fractions, or otherwise simplify your final answer. The symbols \( a \) and \( b \) are constants greater than 1. --- This instruction appears on an educational website to guide students on how to find the derivative of a given function, emphasizing that simplification of the final answer is not necessary. Constants \( a \) and \( b \) are specified to be greater than 1 for clarity.
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