Q1: For the cascaded system of Fig. 1, determine: (a) The loaded voltage gain of each stage.(b) The total gain of the system, Av and Avs.(c) The loaded current gain of each stage.(d) The total current gain of the system.(e) How Zi is affected by the second stage and RL.(f) How Zo is affected by the first stage and Rs.(g) The phase relationship between Vo and Vi.
Q1: For the cascaded system of Fig. 1, determine: (a) The loaded voltage gain of each stage.(b) The total gain of the system, Av and Avs.(c) The loaded current gain of each stage.(d) The total current gain of the system.(e) How Zi is affected by the second stage and RL.(f) How Zo is affected by the first stage and Rs.(g) The phase relationship between Vo and Vi.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![Q1: For the cascaded system of Fig. 1,
determine: (a) The loaded voltage gain of
each stage.(b) The total gain of the system,
Av and Avs.(c) The loaded current gain of
each stage.(d) The total current gain of the
system.(e) How Zi is affected by the second
stage and RL.(f) How Zo is affected by the
first stage and Rs.(g) The phase relationship
between Vo and Vi.
R,
10 μ
Emitter - follower
CE amplifier
1 k2
10uF
Z = 50 k2
Z, = 1.2 k2
R
2.2 k2
Z,= 20 2
Z,= 4.6 k2
= -640
Au
Fig;1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcb1c0b25-4711-4883-8dd1-d9cbededdb8e%2F4045a2cd-32a3-48cf-baf0-ce514b9841f4%2Frvsy47_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q1: For the cascaded system of Fig. 1,
determine: (a) The loaded voltage gain of
each stage.(b) The total gain of the system,
Av and Avs.(c) The loaded current gain of
each stage.(d) The total current gain of the
system.(e) How Zi is affected by the second
stage and RL.(f) How Zo is affected by the
first stage and Rs.(g) The phase relationship
between Vo and Vi.
R,
10 μ
Emitter - follower
CE amplifier
1 k2
10uF
Z = 50 k2
Z, = 1.2 k2
R
2.2 k2
Z,= 20 2
Z,= 4.6 k2
= -640
Au
Fig;1
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