Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is theRockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think aboutthe difference in hardness number between the center and surface (d) Differentiate between hardnessand hardenability (e) Rank the steels in the figure below from lowest to highest hardenability andexplain why.Cooling rate at 700°C (°C/sec)300150011/3 55100600Bar diameter (mm)806040200OLL00ww25 12.5 85S--------------M-R103/4-RAgitated oil15 201/43/4Distance from quenched end. De(Jominy distance)5.543Bar diameter (in.)025 mm1 in.Hardness (Rockwell C)Where (C = center, S = surface, M-R mid-radius)656055504540353025201510010120Distance from quenched end (mm)5140130L2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32Distance from quenched end (sixteenths of an inch)43404098404140864050

Answered: Image /qna-images/answer/15439f6a-9066-4ae7-b9fb-34c7d800457c.jpg

Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. 300 60055 100 Bar diameter (mm) 80 60 40 20 0 Cooling rate at 700°C (°C/sec) 0 5 25 10 12.5 M-R 34-R Agitated oil hi 15 20 14 1/2 3/4 Distance from quenched end, De (Jominy distance) 5.5 3 2 Bar diameter (in.) 0 25 mm 1 in. Where (C = center, S = surface, M-R = mid-radius) Hardness (Rockwell C) 65 60 55 30 25 20 15 10 10 5140 20 30 Distance from quenched end (mm) 4340 24 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 40 9840 4140 8640 50

Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. 300 60055 100 Bar diameter (mm) 80 60 40 20 0 Cooling rate at 700°C (°C/sec) 0 5 25 10 12.5 M-R 34-R Agitated oil hi 15 20 14 1/2 3/4 Distance from quenched end, De (Jominy distance) 5.5 3 2 Bar diameter (in.) 0 25 mm 1 in. Where (C = center, S = surface, M-R = mid-radius) Hardness (Rockwell C) 65 60 55 30 25 20 15 10 10 5140 20 30 Distance from quenched end (mm) 4340 24 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 40 9840 4140 8640 50

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: A cold worked Al-alloy component takes 200 minutes to recrytallize at 250 °Č but takes 14 minutes at…

A: Solution: Given Data: t1=200 minutesT1=250oCt2=14 minutesT2=276oCT3=320oC…

Q: A shear pin made from a 4340 steel (0.4% C) fails by ductile fracture. It was supposed to be…

A: Given: Let us consider the given statements, a) Insufficiently heating the steel would result in…

Q: aluminum alloy 2014

A: Problem asked to specify a practical heat treatment for a 2014 aluminum alloy that will produce a…

Q: The yield region for steel that has a normal grain diameter of 2.4x10-2 mm is 260 MPa. At a grain…

Q: A copper-zinc alloy has the following properties: Grain Diameter (mm) Strength (MPa)…

Q: An aluminum bar (6061-T4) is initially 225.00 mm long at a temperature of 20 C. It is placed between…

A: Given:Initial temperature of aluminum, Ti=20o CFinal temperature of aluminum, Tf=205o CCoefficient…

Q: If we use a 4340; 4140; 8640; 5140; 1040 steel, what would be the hardness number at the center of…

A: First go to Figure below and draw a horizontal line from 1.5 in. diamater and intersect it with…

Q: The fatigue life of a certain steel was found to be 10* cycles at + 70 MPa and 10 cycles at + 50…

Q: Which of the following startements is incomeef? A Under and fatigne 1oa0ding materials may fail at…

A: The incorrect statement out of the above given statements is option (D) (D) Choosing the material…

Q: Consider 1.0 kg of a 99.4 wt% Fe-0.6 wt% C alloy that is cooled to a temperature just below the…

Q: A piston, 9 cm in diameter, is used to increase the internal pressure in a cylinder from 0 to 50…

A: The diameter of the piston is .The yield strength of the cylinder is .The fracture toughness of the…

Q: 8- For the S-N plot below, determine the following: a. What is the fatigue limit for this alloy? b.…

A: Given: The stress amplitude is σa1=400 MPa and σa2=255 MPa. Concept used: Fatigue limit: The number…

Q: 2) A 1 in Dia x 3 in long mild steel hammer head is to be heat treated for surface hardening. If the…

Q: The yield strength for an alloy that has an average grain diameter of 1.6 × 10² mm is 320 MPa. At a…

Q: Figure 11.20 For cylindrical specimens of an oil-quenched 4140 steel, (a) tensile strength, (b)…

Q: For the alloy Mg-45 wt % Pb alloy at 500°C, what is the weight percentage of Pb in Liquid? It does…

A: Given: The wt percentage of Pb, Co = 45 The temperature of alloy, T = 500 C

Q: With respect to the S-N diagram shown below, answer the following questions: (a) for Gray cast iron,…

A: Part (a) Mark the value of 20,000 psi on the vertical axis. Move to the right and mark a point at…

Q: The yield strength for an alloy that has an average grain diameter of 5.3 x 10-2 mm is 146 MPa. At a…

Q: 2. Immediately after recrystallization during annealing, this alloy was quickly cooled. Assume that…

A: Based on the information provided, the likely mechanism for the increase in yield strength (σy)…

Q: Using Figure 4-1 (ductility (%El) - percent cold work), determine the change in cross section of a…

Q: O The following engineering stress-strain data were obtained for a 0.2% C plain-carbon steel. (i)…

A: The stress – strain diagram for the given data is to be drawn . The diagram is drawn using MS Excel.…

Q: Determine the structural constitution of a steel with 0.4% carbon at 727ºC during its cooling.…

A: The iron-carbon phase diagram is a graphical representation of the phase behavior of an iron-carbon…

Q: Question-7. Steady-state creep data taken for an alloy at a stress level of 160 MPa are given below.…

A: Given, Data for stress level of 160 MPa The stress component , n =6.8 R = 8.3145 J/mol-K To find…

Concept explainers

Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the
Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about
the difference in hardness number between the center and surface (d) Differentiate between hardness
and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and
explain why.
Cooling rate at 700°C (°C/sec)
300
150
011/3 55
100
600
Bar diameter (mm)
80
60
40
20
0
OLL
0
0
ww
25 12.5 8
5
S
--------------
M-R
10
3/4-R
Agitated oil
15 20
1/4
3/4
Distance from quenched end. De
(Jominy distance)
5.5
4
3
Bar diameter (in.)
0
25 mm
1 in.
Hardness (Rockwell C)
Where (C = center, S = surface, M-R mid-radius)
65
60
55
50
45
40
35
30
25
20
15
10
0
10
1
20
Distance from quenched end (mm)
5140
1
30
L
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32
Distance from quenched end (sixteenths of an inch)
4340
40
9840
4140
8640
50

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Types of Properties of Engineering Materials

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Handwritten solution required Subject: MS/mechanical
How would you solve this problem
A copper-zine alloy has the properties shown in the table below. Grain Diameter (mm) Strength (MPa) 0.015 170 MPa 0.025 158 MPa 0.035 151 MPa 0.050 145 MPa Determine (a) the constants in the Hall-Petch equa- tion; and (b) the grain size required to obtain a strength of 200 MPa.
For a steel alloy, specify the amount of deformation (%CW) that is necessary to give a minimum Brinell hardness of 225 and at the same time provide a ductility of at least 12%EL. You may need to use Animated Figure 7.19b and Animated Figured 7.19c. There are 2 answers.
Please be sure.
If you could produce AISI 1020 steel with a grain size of 50 nm, what would be the expectedyield stress, assuming a Hall--Petch response? (  MPa, k=0.56 MN/m3/2). Explain eachterm in H-P relation.
Stuck need help! Problem is attached. please view attachment before answering. Really struggling with this concept. Please show all work so I can better understand ! Thank you so much.
800 A Eutectoid temperature H 1400 700 A H 1200 600 1000 500 B 800 400 A 300 600 M(start) 200 M + A 50% 400 M(50%) M(90%) 100 200 10-1 1 10 102 103 104 105 Time (s) Using the isothermal transformation diagram for an iron-carbon alloy of eutectoid composition, specify the final microstructure and approximate amount of each. Assume a small specimen has been held long enough to have achieved a complete and homogeneous austenitic structure prior to treatment. Sample (1): Quickly cool specimen from 800°C to 575°C, hold for 10 s, then quench to room temperature. Sample (2): Quickly cool specimen from 800°C to 500°C, hold for 100 s, then quench to room temperature. O after treatment, sample 1 is 50% pearlite, 50% austenite O after treatment, sample 2 is bauxite O after treatment, sample 1 is 25% pearlite O after treatment, sample 2 is bainite O after treatment, sample 2 is austenite O None of the answers is correct. O after treatment, sample 2 is coarse pearlite O after treatment, sample 1 is…
For each question, provide an explanation, identifying the correct choice ( it is marked in red) and explaining why it's the right answer, as well as why the other options are incorrect. Please do 1, 2.
Please answer question with as much detail as possible Please Use the “NCEES FE Reference Handbook 10.0.1” which can be downloaded for Free from https://ncees.org/ as your Reference for tables and formulas
N MPa = 10 2.2. When the Hall-Petch coefficient is 20 GPa nm/2, estimate the grain size of this alloy after recrystallization. -1/2 d O=O₂+ Kuda куба го вра има че app MPa = 150 MPa + 20 × 10 °MPant -150MPa 1
(ii) The turbine blade root is found to contain a surface fatigue crack of 3.3 mm during a routine maintenance inspection. The major stop-start load cycle is experienced twice per day with a minimum stress of 34 MPa and a maximum stress of 195 MPa. The turbine blade has a KIC of 75 MPa√m. Fatigue crack growth rate data for this alloy is given by: the Paris law constant, A = 4.5 x 10-11 and the Paris law exponent, m = 3.8. How many more stop-starts would you recommend be used? Explain your reasoning. You can assume the shape factor Q = 1.2, K is in MPaNm and a (crack length) is in m