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- Flying Circus of Physics Kiting during a storm. The legend that Benjamin Franklin flew a kite as a storm approached is only a legend – he was neither stupid nor suicidal. Suppose a kite string of radius 2.07 mm extends directly upward by 0.809 km and is coated with a 0.514 mm layer of water having resistivity 177 Q-m. If the potential difference between the two ends of the string is 190 MV, what is the current through the water layer? The danger is not this current but the chance that the string draws a lightning strike, which can have a current as large as 500 000 A (way beyond just being lethal). Number i UnitsIf gold (PAu = 2.44 x 10-8 N. m) and silver (PAg = 1.59 × 10-8 n. m) wires of equal length are found to have the same resistance. 4 a) Find the ratio of their radii (rAL/r Cu)? b) Which element (Au or silver) is better for conducting electrical current? Explain. LEGO102 C 3. For the circuit at right, find: 102 Paralel (a) The current at pts. A, B, C, D, & E. The power dissipated by each resistor. (c) The power supplied by the battery. (d) The potential differences VB- VA, Vc- VB, VD-Vc, VE-VA. 100 V E
- Power Rating of a Resistor. The power rating of a resistor is the maximum power the resistor can safely dissipate without too great a rise in temperature and hence damage to the resistor. (a) If the power rating of a 15 k 2 resistor is 5.0 W, what is the maximum allowable potential difference across the terminals of the resistor? (b) A 9.0 k resistor is to be connected across a 120 V potential difference. What power rating is required? (c) A 100.0 and a 150.0 resistor, both rated at 2.00 W, are connected in series across a variable potential difference. What is the greatest this potential difference can be without overheating either resistor, and what is the rate of heat generated in each resistor under these conditions?X N 3) Consider a cube whose center is at the origin, and all edges of the cube are 4 cm. A battery (DC voltage) with voltage of Vo is connected to bottom and top faces (sides) of cube as shown in left figure. a) If the volume current density in cube is given as; J=100 V₁ (x² + y²)â. A/m² then find the (DC) resistance of the structure. Hint: You can get the result without considering below part (part b). O= b) By assuming that electric field intensity is zero outside the cube (although practically there is nonzero electric field outside the cube, assume that this electric field is very small), if the conductivity of the material of the cube is given as; x² 1+ Z 0.02 10-2 S m then find and express free charge densities (where they exist) in terms of battery voltage Vo. Take cube material's relative permittivity (dielectric constant) as &r = 1.Number 2. Show the step please.