I X N 3) Consider a cube whose center is at the origin, and all edges of the cube are 4 cm. A battery (DC voltage) with voltage of Vo is connected to bottom and top faces (sides) of cube as shown in left figure. a) If the volume current density in cube is given as; J=100 V (x² + y²)â__ A/m² then find the (DC) resistance of the structure. Hint: You can get the result without considering below part (part b). 0 = b) By assuming that electric field intensity is zero outside the cube (although practically there is nonzero electric field outside the cube, assume that this electric field is very small), if the conductivity of the material of the cube is given as; x² + y² 1+ 0.02 10-2 S m then find and express free charge densities (where they exist) in terms of battery voltage Vo. Take cube material's relative permittivity (dielectric constant) as as &₁ = 1.
I X N 3) Consider a cube whose center is at the origin, and all edges of the cube are 4 cm. A battery (DC voltage) with voltage of Vo is connected to bottom and top faces (sides) of cube as shown in left figure. a) If the volume current density in cube is given as; J=100 V (x² + y²)â__ A/m² then find the (DC) resistance of the structure. Hint: You can get the result without considering below part (part b). 0 = b) By assuming that electric field intensity is zero outside the cube (although practically there is nonzero electric field outside the cube, assume that this electric field is very small), if the conductivity of the material of the cube is given as; x² + y² 1+ 0.02 10-2 S m then find and express free charge densities (where they exist) in terms of battery voltage Vo. Take cube material's relative permittivity (dielectric constant) as as &₁ = 1.
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N
3) Consider a cube whose center is at the origin, and all
edges of the cube are 4 cm. A battery (DC voltage) with
voltage of Vo is connected to bottom and top faces
(sides) of cube as shown in left figure.
a) If the volume current density in cube is given as;
J=100 V₁ (x² + y²)â. A/m²
then find the (DC) resistance of the structure.
Hint: You can get the result without considering below part (part b).
O=
b) By assuming that electric field intensity is zero outside the cube (although practically there is
nonzero electric field outside the cube, assume that this electric field is very small), if the
conductivity of the material of the cube is given as;
x²
1+
Z
0.02
10-2 S
m
then find and express free charge densities (where they exist) in terms of battery voltage Vo. Take
cube material's relative permittivity (dielectric constant) as &r = 1.
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