Two batteries with emf &₁ and E2, with internal resistances ₁ and ₂ respectively, are connected as shown in the diagram below. (Assume ₁ = 12 V and r₁=1 N.) | www (a) Calculate the magnitude and indicate the direction of flow of current in the figure shown above. E₂ = 33.0 V and r₂ = 0.65 0. 60 X What is the net voltage when the two batteries are connected in opposition to each other? What is the net internal resistance of this circuit? A counterclockwise magnitude direction (b) Find the terminal voltage of each battery. V₁ = 48 X What is the sign of the current if it is flowing into the positive terminal of the battery? V V₂ = 6 X What is the sign of the current if it is flowing into the positive terminal of the battery? V

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### Circuit Analysis with Two Batteries

Two batteries with emf \( \mathcal{E}_1 \) and \( \mathcal{E}_2 \), and internal resistances \( r_1 \) and \( r_2 \) respectively, are connected as shown in the diagram below. We assume \( \mathcal{E}_1 = 12 \, \text{V} \) and \( r_1 = 1 \, \Omega \).

**Diagram Overview:**
- Two batteries are shown with their internal resistances in series.
- Battery 1 has emf \( \mathcal{E}_1 \) and internal resistance \( r_1 \).
- Battery 2 has emf \( \mathcal{E}_2 = 33.0 \, \text{V} \) and internal resistance \( r_2 = 0.65 \, \Omega \).

### Part (a)
**Objective:** Calculate the magnitude and direction of the current flow in the circuit.

- **Input:**
  - Magnitude: [User entered 60]
  - Direction: [Counterclockwise selected]

- **Error Notes:**
  - The question prompts clarification on the net voltage when the batteries are in opposition and the net internal resistance.

### Part (b)
**Objective:** Determine the terminal voltage of each battery.

- **Calculated Terminal Voltages:**
  - \( V_1 = 48 \, \text{V} \) [Incorrect]
  - \( V_2 = 6 \, \text{V} \) [Incorrect]

- **Error Notes:**
  - The question focuses on the sign of the current when flowing into the positive terminal of each battery.

This analysis illustrates common issues faced in simple circuit problems involving multiple batteries with internal resistances. The errors suggest a need to review concepts of net voltage and internal resistance in series circuits.
Transcribed Image Text:### Circuit Analysis with Two Batteries Two batteries with emf \( \mathcal{E}_1 \) and \( \mathcal{E}_2 \), and internal resistances \( r_1 \) and \( r_2 \) respectively, are connected as shown in the diagram below. We assume \( \mathcal{E}_1 = 12 \, \text{V} \) and \( r_1 = 1 \, \Omega \). **Diagram Overview:** - Two batteries are shown with their internal resistances in series. - Battery 1 has emf \( \mathcal{E}_1 \) and internal resistance \( r_1 \). - Battery 2 has emf \( \mathcal{E}_2 = 33.0 \, \text{V} \) and internal resistance \( r_2 = 0.65 \, \Omega \). ### Part (a) **Objective:** Calculate the magnitude and direction of the current flow in the circuit. - **Input:** - Magnitude: [User entered 60] - Direction: [Counterclockwise selected] - **Error Notes:** - The question prompts clarification on the net voltage when the batteries are in opposition and the net internal resistance. ### Part (b) **Objective:** Determine the terminal voltage of each battery. - **Calculated Terminal Voltages:** - \( V_1 = 48 \, \text{V} \) [Incorrect] - \( V_2 = 6 \, \text{V} \) [Incorrect] - **Error Notes:** - The question focuses on the sign of the current when flowing into the positive terminal of each battery. This analysis illustrates common issues faced in simple circuit problems involving multiple batteries with internal resistances. The errors suggest a need to review concepts of net voltage and internal resistance in series circuits.
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