Q/ A 2 lb weight on a spring stretches it to (0.125 Ft) the weight is pulled Ft below the equilibrium Position assume a damping force numerically equals to 2v .find the position of the weight at any time. Note ( Hooke's Law F = kx and mass m = g = 32)

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QL A 2 lb weight on a spring stretches it to (0.125 Ft) the weight is pulled Ft below the
equilibrium Position assume a damping force numerically equals to 2v .find the position
of the weight at any time. Note ( Hooke's Law F = kx and mass m =
•g = 32)
%3!
Transcribed Image Text:QL A 2 lb weight on a spring stretches it to (0.125 Ft) the weight is pulled Ft below the equilibrium Position assume a damping force numerically equals to 2v .find the position of the weight at any time. Note ( Hooke's Law F = kx and mass m = •g = 32) %3!
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