Q/ A 2 lb weight on a spring stretches it to (0.125 Ft) the weight is pulled Ft below the equilibrium Position assume a damping force numerically equals to 2v .find the position of the weight at any time. Note ( Hooke's Law F = kx and mass m = g = 32)
Q/ A 2 lb weight on a spring stretches it to (0.125 Ft) the weight is pulled Ft below the equilibrium Position assume a damping force numerically equals to 2v .find the position of the weight at any time. Note ( Hooke's Law F = kx and mass m = g = 32)
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![QL A 2 lb weight on a spring stretches it to (0.125 Ft) the weight is pulled Ft below the
equilibrium Position assume a damping force numerically equals to 2v .find the position
of the weight at any time. Note ( Hooke's Law F = kx and mass m =
•g = 32)
%3!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc25ed3c2-df1c-491e-9655-ad66a8d568b9%2F10c389cf-0ae2-4db5-99e5-2a589a164582%2Fp9zubwd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QL A 2 lb weight on a spring stretches it to (0.125 Ft) the weight is pulled Ft below the
equilibrium Position assume a damping force numerically equals to 2v .find the position
of the weight at any time. Note ( Hooke's Law F = kx and mass m =
•g = 32)
%3!
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