(Recall mx" + Bx' + kx 0 and m weight .) A weight of 64 pounds 32 stretches a spring 2 feet. A damping device imparts a damping force numerically equal to 16 times the instantaneous velocity. The initial position is x (0) = 2 and the initial velocity is x' (0) = -1 . This is the equation of motion for the mass. O r = (-2t - 1) e t x = (-7t – 2) e 4t cos(2t) + e 4 sin(2t) 2t O x = 2e -4t O x = (7t + 2) e

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Chapter1: Units, Trigonometry. And Vectors
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weight
.) A weight of 64 pounds
(Recall mx" + Bx' + kx
stretches a spring 2 feet. A damping device imparts a damping force
0 and m
32
numerically equal to 16 times the instantaneous velocity. The initial position is
x (0) = 2 and the initial velocity is x' (0) = –1 . This is the equation of
motion for the mass.
-4t
x = (-2t – 1) e t
-4t
O x = (-7t – 2) eAt
-2t
O x = 2e
cos(2t) +e t sin(2t)
-4t
O x = (7t + 2) e
Transcribed Image Text:weight .) A weight of 64 pounds (Recall mx" + Bx' + kx stretches a spring 2 feet. A damping device imparts a damping force 0 and m 32 numerically equal to 16 times the instantaneous velocity. The initial position is x (0) = 2 and the initial velocity is x' (0) = –1 . This is the equation of motion for the mass. -4t x = (-2t – 1) e t -4t O x = (-7t – 2) eAt -2t O x = 2e cos(2t) +e t sin(2t) -4t O x = (7t + 2) e
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