A spring hangs with its fixed upper end. An object with 59 g mass at its inner end stretches it 9.8 cm. Then this object is replaced by another whose mass is 7kg and once it reaches its equilibrium position the object is brought up 0.09m and released without impulse. The object receives an external force equivalent to 12cos(2y) dynes and not damping forces. If the positive direction is taken| downward, then a differential equation and initial conditions that allow Determining the position x (t), in cm, of the object is: If necessary use gravity g as g = 989 cm / s²
A spring hangs with its fixed upper end. An object with 59 g mass at its inner end stretches it 9.8 cm. Then this object is replaced by another whose mass is 7kg and once it reaches its equilibrium position the object is brought up 0.09m and released without impulse. The object receives an external force equivalent to 12cos(2y) dynes and not damping forces. If the positive direction is taken| downward, then a differential equation and initial conditions that allow Determining the position x (t), in cm, of the object is: If necessary use gravity g as g = 989 cm / s²
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Transcribed Image Text:A spring hangs with its fixed upper end. An object with 59 g mass at its inner
end stretches it 9.8 cm. Then this object is replaced by another whose mass is
7kg and once it reaches its equilibrium position the object is brought up 0.09m
and released without impulse. The object receives an external force equivalent
to 12cos(2y) dynes and not damping forces. If the positive direction is taken|
downward, then a differential equation and initial conditions that allow
Determining the position x (t), in cm, of the object is:
If necessary use gravity g as g = 989 cm / s?
O a) 7000z" + 5900z = 12 cos(2t), ¤(0) = –9, ď'(0) = 0
O b) 590z" + 5900z = 12 cos(2t), æ(0) = -9, z'(0) = 0
Oc) 59z" + 9.8z = 12 cos(2t), ¤(0) = 9, x'(0) = 0
Od) 7000z" + 5900z = 12 cos(2t), x(0) = 9, z'(0) = 0
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Given that:
The positive direction is taken in downward direction
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