A lkg mass is suspended from a spring with spring constant k = 1 and damping cocfficient y 0.125. An external force is applied F = should take the Laplace transform, solve for Y, then use Wolfram Alpha to get plot the inverse Laplace transform (i.c. solution to the differential cquation) for 0
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- Problem 2: A 200 g oscillator is oscillating at 2.0 Hz in a vacuum chamber. When air is admitted, the amplitude drops 60% in 50 s. How many oscillations will have been completed when the amplitude is 30% of its initial value?Consider that a rigid bar is connected to a wall via a free rotating joint, and the spring maintains the bar in a horizontal position, as shown below. Ignore the radius of the bar. 60cm lllllll 80cm Specify the resting length of the spring in cm. Assume that mass of the bar is 10 kg and is uniformly distributed, gravitational acceleration is 9.8 m/s^2, and the spring constant is 1000 N/m. Round the answer to the nearest integer, and input the number only.2 Consider a particle of mass m moving in the region x > 0 under the influence of a potential U (x) = Uo а xc + х а where Uo and a are positive constants. Sketch the potential, find the equilibrium point, and determine its sta- (a) bility. Find the frequency of small oscillations about the stable equilibrium (b) point.
- Answer both Q1: An object undergoes simple harmonic motion. As itmomentarily passes through the equilibriumposition, which statement is true about its potentialenergy U and kinetic energy K?minimum U, minimum Kmaximum U, maximum Kminimum U, maximum Kmaximum U, minimum KNone of the above 2. An object undergoes simple harmonic motion. When itstops at its turnaround points, which of thefollowing statements is true about its potential energy U andkinetic energy K?minimum U, maximum Kminimum U, minimum Kmaximum U, minimum Kmaximum U, maximum KNone of the aboveA wheel is free to rotate about its fixed axle. A spring is attached to one of its spokes at distance r from the axle. Assuming that the wheel is a hoop of mass m and radius R, what is the angular frequency w of small oscillations of this system in terms of m, R, r, and the srping constant k? What is w if r =R and if r = 0? Thank you for the help. I think I'm tripping myself up with using r in the equations.Consider a particle of mass m attached to two idenfical springs YA ZILLII|////. each of length 1 and spring constant k (see the figure). The equilibrium configuration is the one wheie the springs are unstretched. There are no other external 1orces on the system. lr the particle is given a small displacement along the x-axis, which of the following describes the equation of mouon for small oscillations? lll
- A block of mass m = 3kg is attached to a light spring with a spring constant k and moves in simple harmonic motion on a frictionless horizontal surface. Initially the spring is compressed to x, = -–0.1 m from its equilibrium position and is given an initial velocity vo in the negative x-direction, as shown in the figure below. The maximum speed reached by the block is vmax = v2 m/s. The block's period of oscil- lation is T= 0.889s. 3) The velocity of the block att = 0, vo is: hmmo Equilibnura aV2 m/s b. V2 m/s e. -1 224 m/s d 1224 m/s wwwA mass of 55 grams stretches a spring by 8 cm. (Note that this means the forces balance, and thus mg = kx where m = 55 grams is mass, g = 981 cm/s is acceleration due to gravity, k is the spring constant, and x = 8 cm is the displacement.) The mass is set in motion from this equilibrium position with an initial downward velocity of 23 cm/s, and there is no damping. Find the position u (in cm) of the mass at any time t (in s). (Assume that position is measured upward from the equilibrium position.) u(t) Find the frequency (in radians per second), period (in seconds), and amplitude (in cm) of the motion. Frequency is Period is Amplitude isstraight line is always acted upon by a force from the centre of the path and directed Ex. 2: A particle of mass 8 gm moving in a and maximum acceleration, if the amplitude is towards the centre. Find its maximum velocity sse magnitude is 128 times the displacement 5 cm.
- Consider the simple pendulum: a ball hanging at the end of a string. Derive the expression for the period of this physical pendulum, taking into account the finite size ball (i.e. the ball is not a point mass). Assume that the string is massless. Start with the expression for the period T'of a physical pendulum with small amplitude oscillati T = 2π The moment of inertia of the ball about an axis through the center of the ball is Here, I, is the moment of inertia about an axis through the pivot (fixed point at the top of the string, m is the mass of the ball, g is the Earth's gravitational constant of acceleration, and h is the distance from the pivot at the top of the string to the center of mass of the ball. Note, this pre-lab asks you to do some algebra, and may be a bit tricky. I mgh Iball = / mr² TConsider a mass m attached to a spring with natural length 7, hanging vertically under the action of gravity mgk (where the unit vector k is pointing downwards) and a constant friction force F =-Fok. (a) Find the equilibrium point of the mass, write the equation of motion, and show that the motion of the particle is governed by the fundamental equation of simple harmonic motion. (b) Assume the particle is released from the spring when it has heighth above ground and initial velocity vo. Let y be the height above ground of the particle (note that the orientation of the axis is now opposite of z used in point (a)). Write the equation of motion (under the action of gravity and the friction force F). Solve them for the given initial condition and show that v(y)² = vz+2(g− ¹)(h—−y) m (c) Upon entering the ground (y=0) with velocity v₁, the particle is subject to a constant friction force F₁ where F₁ >0 is a constant. Calculate the distance d travelled by the particle into the ground in…Question 1. Find the steady state solution of the forced Mass-Spring-Damper with the following parameters undergoing forcing function F(t). 3 kg, c = 22 Ns/m, k = 493 N/m, F(t) = 21 cos(6t) in the form of (t) = A cos(6t – 8) Enter your answers for A and to four decimal places in the appropriate boxes below: m = A: d: