Consider a 3 kg object attached to a hanging spring with spring constant 75 N/m. Assume the system is undamped but has an external force Fe(t) = 10 cos(5t), If the spring is initially stretched 0.2 m past its resting position and given an upward initial velocity of 0.1 m/s, find a formula for the location of the mass at any time t. As in class, we will take the downward direction to be the positive direction of motion. x(t) = (t1)cos(5t)+(t2)sin(5t)-0.5cos(5t)
Consider a 3 kg object attached to a hanging spring with spring constant 75 N/m. Assume the system is undamped but has an external force Fe(t) = 10 cos(5t), If the spring is initially stretched 0.2 m past its resting position and given an upward initial velocity of 0.1 m/s, find a formula for the location of the mass at any time t. As in class, we will take the downward direction to be the positive direction of motion. x(t) = (t1)cos(5t)+(t2)sin(5t)-0.5cos(5t)
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
Transcribed Image Text:Consider a 3 kg object attached to a hanging
spring with spring constant 75 N/m. Assume the
system is undamped but has an external force
Fe(t) = 10 cos(5t),
If the spring is initially stretched 0.2 m past its resting
position and given an upward initial velocity of 0.1 m/s,
find a formula for the location of the mass at any time t.
As in class, we will take the downward direction to be
the positive direction of motion.
x(t) =
=
(t1)cos(5t)+(t2)sin(5t)-0.5cos(5t)
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