Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg. The block undergoes SHO (simple harmonic motion) with no friction. At time t = 0.1818 s, the position and velocity of the block are x(0.1818 s) -0.08836 m v(0.1818 s) = 0.9604 m/s Part (a) What was the position, in meters, at t= 0.00 s? x(0.00 s)=1 m Part (b) What was the velocity, in meters per second, at t= 0.00 s?
Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg. The block undergoes SHO (simple harmonic motion) with no friction. At time t = 0.1818 s, the position and velocity of the block are x(0.1818 s) -0.08836 m v(0.1818 s) = 0.9604 m/s Part (a) What was the position, in meters, at t= 0.00 s? x(0.00 s)=1 m Part (b) What was the velocity, in meters per second, at t= 0.00 s?
Related questions
Question
Needs Complete typed solution with 100 % accuracy.
![Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg.
The block undergoes SHO (simple harmonic motion) with no friction. At time t= 0.1818 s, the position and velocity of the block are
Part (a) What was the position, in meters, at t= 0.00 s?
x(0.00 s) = 1
m
x(0.1818 s) = -0.08836 m
v(0.1818 s) = 0.9604 m/s
Part (b) What was the velocity, in meters per second, at t = 0.00 s?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4f86639-ba56-4174-ae93-22737ea6ea05%2F6ffacf68-cde6-4cda-a3d5-9465ed770e7a%2Fb5khgze_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 1: One end of a spring with a spring constant of 159 N/m is held firmly in place, and the other end is attached to a block with a mass of 2.13 kg.
The block undergoes SHO (simple harmonic motion) with no friction. At time t= 0.1818 s, the position and velocity of the block are
Part (a) What was the position, in meters, at t= 0.00 s?
x(0.00 s) = 1
m
x(0.1818 s) = -0.08836 m
v(0.1818 s) = 0.9604 m/s
Part (b) What was the velocity, in meters per second, at t = 0.00 s?
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)