Q (5-2)/ Water flows uniformly in an earth rectangular cross section open channel. Data available are: Bed width of the channel B= 20 y (m), longitudinal slope of bed level of the channel S. 0.0001, n =0.017 {s/m(13)) and water flow rate Q=150 (m³/s). = Calculate values of the followings: 1- Bed width of the channel B. 2- Water flow depth in the channel y. 3- Fruid Number Fr. 1911 (m/s), Fr= 0.2 less than 1. Flow is sub-critical (slow flow). (m) 0000010001001-3 narts oilt to yomiq banW.9 +4=¹(3+1)+8 (m) 24.5 ANSWER/ A=0.05B², P= 1.1 B, B = 53.42 (m), y = 2.67 (m), A = 142 (m²), v = 1.05 JUMPS 01400021 Cas ONSDOIR

Q (5-2)/ Water flows uniformly in an earth rectangular cross section open channel. Data available are: Bed width of the channel B= 20 y (m), longitudinal slope of bed level of the channel S. 0.0001, n =0.017 {s/m(13)) and water flow rate Q=150 (m³/s). = Calculate values of the followings: 1- Bed width of the channel B. 2- Water flow depth in the channel y. 3- Fruid Number Fr. 1911 (m/s), Fr= 0.2 less than 1. Flow is sub-critical (slow flow). (m) 0000010001001-3 narts oilt to yomiq banW.9 +4=¹(3+1)+8 (m) 24.5 ANSWER/ A=0.05B², P= 1.1 B, B = 53.42 (m), y = 2.67 (m), A = 142 (m²), v = 1.05 JUMPS 01400021 Cas ONSDOIR

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Highway Drainage

Highway drainage is the process of extracting and regulating the excess surface water on the pavement by giving the desired slope. The construction of a highway drain helps to divert the water present on the surface, and sub-grade by the means of slope. Highway drainage systems are a necessary part of smooth functioning of traffic, since the highway drainage systems provide proper disposal of unwanted substances from the highways.

Question

Q (5-2)/ Water flows uniformly in an earth rectangular cross section open
channel. Data available are:
(45)
Bed width of the channel B= 20 y (m), longitudinal slope of bed level of
the channel S. 0.0001, n = 0.017 {s/m(13)) and water flow rate Q=150
-
(m³/s).
Calculate values of the followings:
1- Bed width of the channel B.
2- Water flow depth in the channel y.
3- Fruid Number Fr.
LA
(ar) 000001-0001 * 001-
antarts out to ystoming bato WA
+5=(3+1) +8
ANSWER/
A=0.05B², P= 1.1 B, B = 53.42 (m), y = 2.67 (m), A = 142 (m²), v= 1.05
01100021
(m/s), Fr= 0.2 less than 1.
Flow is sub-critical (slow flow).
ply to 'm) 016012-re.fx 000seas

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