Water is flowing at a depth d of 12.0 ft with a flow rate per unit width q of 100 ft2/s in a channel of rectangular cross section. a. Calculate (using a root finder) the flow depth in feet over a smooth upward step in the channel bottom of 2 ft in height. (See the figure below.) b. Calculate (using a root finder) the flow depth in feet over a smooth downward step in the channel bottom of 2 ft in height. Draw a figure showing this, like the one below. c. Calculate the maximum possible height in feet of a smooth upward step in the channel bottom that would not cause a choke.
Water is flowing at a depth d of 12.0 ft with a flow rate per unit width q of 100 ft2/s in a channel of rectangular cross section. a. Calculate (using a root finder) the flow depth in feet over a smooth upward step in the channel bottom of 2 ft in height. (See the figure below.) b. Calculate (using a root finder) the flow depth in feet over a smooth downward step in the channel bottom of 2 ft in height. Draw a figure showing this, like the one below. c. Calculate the maximum possible height in feet of a smooth upward step in the channel bottom that would not cause a choke.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Water is flowing at a depth d of 12.0 ft with a flow rate per unit width q of 100 ft2/s in a channel of rectangular cross section.
a. Calculate (using a root finder) the flow depth in feet over a smooth upward step in the channel bottom of 2 ft in height. (See the figure below.)
b. Calculate (using a root finder) the flow depth in feet over a smooth downward step in the channel bottom of 2 ft in height. Draw a figure showing this, like the one below.
c. Calculate the maximum possible height in feet of a smooth upward step in the channel bottom that would not cause a choke.
![100 ft?/s
d2
d, = 12.0 ft/s
2 ft](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F775d5518-05f9-4927-9f72-0cdf8df38abb%2F5b716596-edc9-4f9b-a968-c715774f74e4%2F1eub2t_processed.png&w=3840&q=75)
Transcribed Image Text:100 ft?/s
d2
d, = 12.0 ft/s
2 ft
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