Question 12 of 23 A flow os 0.413 m3/s was measured from a rectangular channel flowing 1.20 m wide and 0.60 m deep. If the slope of the channel was 0.0004, what os the roughness of the lining of the channel? Select the correct response: 0.013 0.025 0.021 0.016 < Previous

Q: Show step by step solu

A: Q=1.555D2Explanation:

Q: You are in charge of evaluating a segment of aqueduct pipe (diameter: 30cm). You know that pt. A has…

A: Diameter = 0.3 m PA = 500 kPa LAB = 100 m QAB = 175 L/s = 0.175 m3/s C = 100 Find: (a) Head lost…

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A: Find resultant of given forces from problem 1 and 2 (Note;Answers given of problem 1 are wrong,i…

Q: This problem refers to the sketch shown in Figure 2. If the discharge in the channel (n = 0.028) is…

A: Manning coefficient (n) = 0.028Discharge (Q) = 6 m3/sec Depth of flow (y) = 1.8m Maximum velocity…

Q: Problem #1 (Pipes Iterative Analysis): Water at 70°F flows through 100 feet of pipe 10 inches in…

A:

Q: (4) The cross-section of a road and gutter are shown below. The slope of the gutter and roadway is…

A: Given  Depth 10 inch  Width 50 inch  Triangular section  Manning's formula  Assume n = 0.014

Q: In 1957 H. Görtler proposed the adverse gradient test cases U =- U. (1 + x/L)" and computed…

A: Given Data: Stream velocity n=1 xsep/L=0.159 θ0=0

Q: A flow test was conducted on an old existing pipeline to determine the coefficient C for the Hazen…

A: C = 63.84Explanation:

Q: downstream direction), and the curb is 10" tall. Assume uniform flow. 1 What is the maximum flow…

A: Using manning formula Width 50 ft Depth 10 ft  Triangular section  Slope 1/400

Q: Situation 5 - A 0.60 m diameter pipeline 30 m long carries 0.4 m^3/s of water.   a. Compute the…

A: given - pipe diameter D = 0.6 m  pipe length L = 30 m  discharge , Q = 0.4 m3/sec

Q: The peak flow data for 5 years is provided in the table below. Based on the table below, what are…

A: Determine the a, b and c value in above table.

Q: 1. If the flow out is 200 mm³/sec in figure 1, find K1 and K2 dh = 0.01 mm/sec, dt 2. In figure 2,…

A:

Q: The mean daily discharge hydrograph from a basin is given below. It is known that the recession limb…

A:

Q: Example 8: A flocculation basin is designed to treat water of 1 m³/s flow rate. The length of the…

A:

Q: Manning's equation is Q = where Cm AR 2/3 1/2 n Q = Cm = = flow (m³/s) 1.49 USC system 1.00 SI…

A: D = 275.3317482 8/3√(Qn/S1/2)Explanation:

Q: Calculate the time of concentration for a concrete parking lot that is 300 ft wide by 600 ft long.…

A: Concentrated flow refers to flow that quickens and deepens, generating narrow channels. Shallow…

Q: form flow of water in a wide channel with a velocity of 8 m/s and flow depth of 0.8 m. Water flows…

A: Data provided-   V1 = 8 m/s , y1 =0.8 m     Total energy at (1) =E1   E1 = y1 +V122g=(0.8+822×9.81)…

Q: hydraulic depth, in ft, is

A:

Q: The peak flow data for 5 years is provided in the table below. Based on the table below, what are…

A: Determine the a, b and c value in above table.

Q: ngure (a) What are the boundaries to this flow field? Label each of the four boundaries, noting the…

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Time and time related variables in engineering

Time is the event progression starting from past to present and then, future statistically. The time-related variable is any particular value in relation to time to assess its changes on a specified (XY) plane.