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How is the energy dissipated in the jump? How can jumps be used in engineering practice?

How is the energy dissipated in the jump? How can jumps be used in engineering practice?

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please use the table to answer the second question
**Questions for Discussion:** 1. **Summarize the energy loss across the jump that you created expressed as a percentage of the upstream energy. Do you consider this significant?** 2. **How is the energy dissipated in the jump? How can jumps be used in engineering practice?** 3. **Calculate the critical depth, and compare them with the conjugate depths observed in the jump.**
Transcribed Image Text:**Questions for Discussion:** 1. **Summarize the energy loss across the jump that you created expressed as a percentage of the upstream energy. Do you consider this significant?** 2. **How is the energy dissipated in the jump? How can jumps be used in engineering practice?** 3. **Calculate the critical depth, and compare them with the conjugate depths observed in the jump.**
**Part 3 – Hydraulic Jump and Critical Depth – C4 Flume** - **Channel width**: 7.6 cm - **Flume Slope**: 3% - **Distance between gauges**: 100 cm --- **Jump Condition Table:** | Jump Condition | y₁ (cm) | y₂ (cm) | z₁ (cm) | z₂ (cm) | Q (cm³/sec) | V₁ (cm/sec) | V₂ (cm/sec) | Computed Hⱼ (cm) | % loss based on Upstream Energy | |----------------|---------|---------|---------|---------|-------------|--------------|--------------|------------------|---------------------------------| | Direct | 1.59 | 11 | 3 | 0 | 1570 | 129.924 | 18.78 | 9.41 | 15.26 | --- **Computed y_c**: 3.5 cm --- **Calculations:** 1. **V₁ = Q / y₁:** - \( V₁ = \frac{1570}{7.6 \times 1.59} \) - \( V₁ = 129.924 \, \text{cm/sec} \) 2. **V₂ = Q / y₂:** - \( V₂ = \frac{1570}{7.6 \times 11} \) - \( V₂ = 18.78 \, \text{cm/sec} \) 3. **Hydraulic Jump (HJ):** - \( HJ = y₂ - y₁ \) - \( HJ = 11 - 1.59 \) - \( HJ = 9.41 \, \text{cm} \) 4. **% Energy Loss:** - \( E_{\text{ups}} = y₁ + z₁ + \frac{V₁^2}{2g} \) - \( E_{\text{ups}} = 1.59 + 3 + \frac{129.924^2}{2 \times 981} \) - \( E_{\text{ups}} \approx 13.1986 \, \text{cm} \) - \( E_{\text{dls
Transcribed Image Text:**Part 3 – Hydraulic Jump and Critical Depth – C4 Flume** - **Channel width**: 7.6 cm - **Flume Slope**: 3% - **Distance between gauges**: 100 cm --- **Jump Condition Table:** | Jump Condition | y₁ (cm) | y₂ (cm) | z₁ (cm) | z₂ (cm) | Q (cm³/sec) | V₁ (cm/sec) | V₂ (cm/sec) | Computed Hⱼ (cm) | % loss based on Upstream Energy | |----------------|---------|---------|---------|---------|-------------|--------------|--------------|------------------|---------------------------------| | Direct | 1.59 | 11 | 3 | 0 | 1570 | 129.924 | 18.78 | 9.41 | 15.26 | --- **Computed y_c**: 3.5 cm --- **Calculations:** 1. **V₁ = Q / y₁:** - \( V₁ = \frac{1570}{7.6 \times 1.59} \) - \( V₁ = 129.924 \, \text{cm/sec} \) 2. **V₂ = Q / y₂:** - \( V₂ = \frac{1570}{7.6 \times 11} \) - \( V₂ = 18.78 \, \text{cm/sec} \) 3. **Hydraulic Jump (HJ):** - \( HJ = y₂ - y₁ \) - \( HJ = 11 - 1.59 \) - \( HJ = 9.41 \, \text{cm} \) 4. **% Energy Loss:** - \( E_{\text{ups}} = y₁ + z₁ + \frac{V₁^2}{2g} \) - \( E_{\text{ups}} = 1.59 + 3 + \frac{129.924^2}{2 \times 981} \) - \( E_{\text{ups}} \approx 13.1986 \, \text{cm} \) - \( E_{\text{dls
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